我有下面的代码文件:Serialize List <ICustomClass> to xml?
public interface IMod
{
string Name { get; set; }
string Description { get; set; }
bool Enabled { get; set; }
List<IClassFile> ClassFiles { get; set; }
}
public interface IClassFile
{
string Path { get; set; }
string FileName { get; set; }
bool Enabled { get; set; }
}
public class ClassFile : IClassFile
{
public string Path { get; set; }
public string FileName { get { return System.IO.Path.GetFileName(Path); } }
public bool Enabled { get; set; }
....
}
public class ZippedMod : IMod
{
public string Name { get; set; }
public string Description { get; set; }
public bool Enabled { get; set; }
public List<IClassFile> ClassFiles { get; set; }
....
}
public class ConfigurationBlock
{
public List<IMod> Mods { get; set; }
....
}
在我的整个程序的过程中,我添加了一些ZippedMod
S到ConfigurationBlock
,但现在我想序列化。我试图做:
using (var stream = new StreamWriter("config.xml"))
{
var ser = new XmlSerializer(typeof(ConfigurationBlock));
ser.Serialize(stream, configBlock);
}
但我得到这个错误:
There was an error reflecting type 'MinecraftModManager.ConfigurationBlock'.
|-Inner Exception:
Cannot serialize member 'MinecraftModManager.ConfigurationBlock.Mods' of type 'System.Collections.Generic.List`1[[MinecraftModManager.IMod, MinecraftModManager, Version=1.0.0.0, Culture=neutral, PublicKeyToken=null]]', see inner exception for more details.
|-Inner Exception:
Cannot serialize member MinecraftModManager.ConfigurationBlock.Mods of type MinecraftModManager.IMod because it is an interface.
帮助?
但我*有*使用接口,否则整个程序将无法正常工作。 – Entity
@TheAdamGaskins一个接口不过是一个具有纯虚拟方法的抽象基类。为什么'必须'它是一个抽象基类的接口? –
啊,误解你的意思是“你必须使用具体类型”。但是将接口更改为抽象类将会奇迹般地修复一切......? – Entity