public class Confusion {
Confusion(int i) {
int j = 5;
int[] a = new int[2];
try {
a[0] = 4;
if (i <= 0) {
int k = j/i;
} else {
System.out.println(j/i);
}
} catch (ArithmeticException sa) {
System.out.println("Wrong value" + sa);
} catch (ArrayIndexOutOfBoundsException e) {
System.out.println("out of range massage in Class");
} finally {
System.out.println("Executing finally block in code");
}
}
void k() {
int[] a = new int[2];
{
try {
a[4] = 4;
} catch (ArrayIndexOutOfBoundsException e) {
System.out.println("out of range");
}
}
}
}
public class Nested {
public static void main(String[] args) {
Confusion c = new Confusion(2);
Confusion c1 = new Confusion(0);
c1.k();
c.k();
}
}
-2
Executing finally block in code
Wrong valuejava.lang.ArithmeticException:/by zero
Executing finally block in code
out of range
out of range
每当我执行finally{}
块下面是越来越两次执行它写在代码中。不知道为什么会发生这种情况。我只想运行一次finally块。 有没有办法在单一方法中抛出多个异常?
因为你说了两次,不是吗? – Leri
而不是在构造函数中有逻辑,并有这种“问题”,你可以将逻辑移动到一个方法,所以它非常简单... 2方法调用= 2'try {} catch {} finally {}'块 – araknoid