使用yii框架从内连接数据库中选择的不显示值

我不能在使用yii的两个表的内连接重复列名称中显示值。我的浏览页面是advance_search_detail.php，控制器sitecontroller.php。我得到错误“Property”Job.Ltitle“未定义”。使用yii框架从内连接数据库中选择的不显示值

控制器是sitecontroller.php

public function actionadvance_search_result() 
{ 
$title=$_GET['title']; 
$experience=$_GET['experience']; 
$location=$_GET['location']; 
$category=$_GET['category']; 
$salary_min=$_GET['salary_min']; 
$salary_max=$_GET['salary_max']; 

$criteria = new CDbCriteria(); 
$criteria->select = 't.title, location.title as Ltitle, t.key_skills, t.description, t.no_vacancy, t.experience, t.company_name, t.salary'; 
$criteria->join = 'INNER JOIN location ON t.location_id = location.id'; 
if($experience!="") 
{ 
$criteria->addCondition("(title like '%$title%' or key_skills like '%$title%') and (experience like '%$experience%')");  
} 
if($location!="") 
{ 
    $criteria->addCondition("location_id like '%$location%'"); 
} 

if($category!="") 
{ 
    $criteria->addCondition("category_id like '%$category%'"); 
} 
if($salary_min!="" && $salary_max!="") 
    { 
     $criteria->addCondition("salary >= '$salary_min' and salary <= '$salary_max'"); 
    } 

$count=Job::model()->count($criteria); 
$pages=new CPagination($count); 
$pages->pageSize=2; 
$pages->applyLimit($criteria); 
$model=Job::model()->findAll($criteria); 
$number_rec=count($model); 
if($number_rec<=0) 
{ 
    $this->render('search_result1',array('model' =>$model)); 
} 
else 
{ 
    $this->render('advance_search_result',array('model' =>$model,'pages' => $pages)); 
}

}

我的看法页面advance_search_result.php

<div> 
<div> 
<h1>Search Results</h1> 
<ul style="list-style:none; "> 
<?php 
    foreach($model as $models) 
    { 
    $job_id=$models->id; 
    ?> 
    <li><p><?php //echo $models->title; ?> 
     <?php echo CHtml::link($models->title, array('site/advance_search_detail', 'job_id'=>$job_id,'status'=>0)); ?></p> 
     <p><?php echo CHtml::link($models->Ltitle); ?></p> 
     <p><?php echo $models->company_name; ?></p> 
     <p><?php echo $models->description; ?></p> 
     <p>Keyskill:<?php echo $models->key_skills; ?><p> 
    </li></br> 
<?php 
    } 
?> 
</ul>  
<p><?php $this->widget('CLinkPager', array('pages' => $pages)) ?></p>

有人帮帮我吗？

来源

2014-05-14 user3514095

首先检查您的两个模型关系，然后将别名设置为位置表。表作业具有别名（t）和设置表位置别名（l）。如下所示

$criteria = new CDbCriteria(); 
$criteria->select = 't.title, l.title as Ltitle, t.key_skills, t.description, 
t.no_vacancy, t.experience, t.company_name, t.salary'; 

$criteria->join = 'INNER JOIN location l ON t.location_id = l.id';

来源

2014-06-16 10:13:51

使用yii框架从内连接数据库中选择的不显示值

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