JAXB - 为不同的元素添加相同的属性

Question

我仔细研究了"JAXB Adding attributes..."的讨论，并想进一步推进。

例如，有下面的类：

@XmlRootElement(name = "company") 
@XmlType(propOrder = {"id", "name", "address"}) 
public class Company { 

    private String id; 
    private String name; 
    private String address; 

    @XmlElement(name = "id") 
    public String getId() { 
     return id; 
    } 

    public void setId(String id) { 
     this.id = id; 
    } 

    @XmlElement(name = "name") 
    public String getName() { 
     return name; 
    } 

    public void setName(String name) { 
     this.name = name; 
    } 

    @XmlElement(name = "address") 
    public String getAddress() { 
     return name; 
    } 

    public void setAddress(String address) { 
     this.address = address; 
    } 
} 

编组对象后，我们有：

<company> 
    <id>1</id> 
    <name>Abc</name> 
    <address>Mountain View, United States</address> 
</company> 

是否有一个优雅的解决方案， - 例如使用注释@XmlPaths，@XmlPath，@XmlElements ，@XmlElement， - 因此收到：

<company> 
    <id>1</id> 
    <name lang="en">Abc</name> 
    <address lang="en">Mountain View, United States</address> 
</company> 

Answer 1

如何用lang属性和使用创建自定义字符串，而不是字符串

例如：

public class LangString { 

    @XmlValue 
    protected String value; 
    @XmlAttribute(name = "lang") 
    @XmlJavaTypeAdapter(CollapsedStringAdapter.class) 
    @XmlSchemaType(name = "language") 
    protected String lang; 

    //GETTERS & SETTERS 
} 

您的代码：

@XmlRootElement(name = "company") 
@XmlType(propOrder = {"id", "name", "address"}) 
public class Company { 

    private String id; 
    private LangString name; 
    private LangString address; 

    @XmlElement(name = "id") 
    public String getId() { 
     return id; 
    } 

    public void setId(String id) { 
     this.id = id; 
    } 

    @XmlElement(name = "name") 
    public LangString getName() { 
     return name; 
    } 

    public void setName(LangString name) { 
     this.name = name; 
    } 

    @XmlElement(name = "address") 
    public LangString getAddress() { 
     return name; 
    } 

    public void setAddress(LangString address) { 
     this.address = address; 
    } 
} 

上面从XSD生成的代码我的应用程序具有lang属性元素的模式，因此为@XmlSchemaType。

希望它有帮助