SQL Server 2008中的问题

我有表结构如下...SQL Server 2008中的问题

 ReturnID SumbitID Status 

      1   1 1 
      1   NULL 2 
      2   2 3 
      3   3 1 
      3   3 1

我想这个输出.....

 RetunrID TotalAttempt Success 
      1  2   1 
      2  1   0 
      3  2   2

计数ReturnID是TotalAttempt，当ReturnID = sumbitID和状态= 1然后它算作成功... 在此先感谢！

来源

2011-09-27 jats

像这样的事情

SELECT 
    T.ReturnID 
, COUNT(T.ReturnID) AS TotalAttempt 
, SUM(CASE WHEN T.ReturnID = T.sumbitID AND T.Status = 1 THEN 1 ELSE 0 END) AS Status 
FROM dbo.MyTable T 
group by T.ReturnID

来源

2011-09-27 03:37:46 billinkc

工作，但你必须在条款最后添加组.... SELECT T.ReturnID ，COUNT（T.ReturnID ）AS TotalAttempt ，SUM（CASE WHEN T.ReturnID = T.sumbitID AND T.Statusa = 1 THEN 1 ELSE 0 END）AS Status FROM @table T GROUP BY T.ReturnID – jats

检查：

SELECT T.ReturnID , COUNT(T.ReturnID) AS TotalAttempt , SUM(CASE WHEN T.ReturnID = T.sumbitID AND T.Statusa = 1 THEN 1 ELSE 0 END) AS Status FROM @table T GROUP BY T.ReturnID

来源

2011-09-27 03:39:49 BizApps

SQL Server 2008中的问题

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