在python烧瓶中上传文件

我正在尝试合并上传一个基本的文本/ csv文件到我的web应用程序，该应用程序运行烧瓶来处理http请求。我试图按照localhost here上运行的烧瓶文档中的宝宝示例。但是，当我在我的页面上尝试这段代码时，它似乎上传，但后来只是挂起，事实上我的瓶服务器冻结，我不得不关闭终端再试一次... Ctrl + C甚至不工作。在python烧瓶中上传文件

我执行run.py：

#!/usr/bin/env python 
from app import app 

if __name__ == '__main__': 
    app.run(host='0.0.0.0', port=5000, debug=False, use_reloader=False)

和app是在同一目录的目录中run.py与以下__init__.py：

import os 
from flask import Flask 
from werkzeug import secure_filename 

#Flask object initialization 
#app flask object has to be created before importing views below 
#because it calls "import app from app" 
UPLOAD_FOLDER = '/csv/upload' 
ALLOWED_EXTENSIONS = set(['txt', 'csv']) 

app = Flask(__name__) 
app.config['UPLOAD_FOLDER'] = UPLOAD_FOLDER

，这里是我的views.py文件，其中有我的所有路由：

from flask import render_template, request, redirect, url_for 
from app import app 
import os 

#File extension checking 
def allowed_filename(filename): 
    return '.' in filename and filename.rsplit('.',1)[1] in ALLOWED_EXTENSIONS 

@app.route('/', methods=['GET', 'POST']) 
@app.route('/index.html', methods=['GET', 'POST']) 
def index(): 
    if request.method == 'POST': 
     submitted_file = request.files['file'] 
     if submitted_file and allowed_filename(submitted_file): 
      filename = secure_filename(submitted_file.filename) 
      submitted_file.save(os.path.join(app.config['UPLOAD_FOLDER'], filename)) 
      return redirect(url_for('uploaded_file', filename=filename)) 

    return ''' 
    <!doctype html> 
    <title>Upload new File</title> 
    <h1>Upload new File</h1> 
    <form action="" method=post enctype=multipart/form-data> 
     <p><input type=file name=file> 
     <input type=submit value=Upload> 
    </form> 
    '''

来源

2015-06-23 ministry

有人可以告诉我字符串“uploaded_file”来自哪里吗？ – computingfreak

问题是你错过了allowed_filename()。你应该通过submitted_file.filename而不是submitted_file本身

来源

2015-06-23 21:06:14 junnytony

哇，这是愚蠢的，谢谢。 – ministry

在python烧瓶中上传文件

回答

相关问题