SQL运行总数从一个计数

如何从计数的数量中获得运行总数？SQL运行总数从一个计数

select Hour, count(*) TotalPerHOur, sum(TotalPerHOur) TotalCumulative 
from table1 
group by Year, Month, Day, Hour

这是我的查询 - 但不工作... 错误我得到的是

无效的列TotalPerHOur

结果表的实施例

HOUR Total_per_Hour Total Cumulative 
6:00-7:00 8      8 
7:00-8:00 13     21 
8:00-9:00 20     41 
9:00-10:00 22     63 
10:00-11:00 10     73 
11:00-12:00 23     96

来源

2014-06-11 nadG

什么DB引擎你用？ –

Microsoft SQL Server管理工作室 – nadG

而你正在得到的错误？ – Ambrish

尝试是这样的：

SELECT t1.Hour, count(*) TotalPerHOur, (
    SELECT count(*) 
    FROM table1 t2 
    WHERE t2.Year <= t1.Year and t2.Month <= t1.Month and t2.Day <= t1.Day and t2.Hour <= t1.Hour 
) TotalCumulative 
FROM table1 t1 
GROUP BY t1.Year, t1.Month, t1.Day, t1.Hour

在SQL Fiddle。

来源

2014-06-11 09:10:00 cy3er

你得到这个错误，因为TotalPerHOur我尚未定义。你正在用它来计算TotalCumulative。

以下查询应该工作：

SELECT 
    Hour, 
    TotalPerHOur, 
    sum(TotalPerHOur) TotalCumulative 
FROM (
    SELECT 
     Hour, 
     count(*) TotalPerHOur 
    FROM 
     table1 
    GROUP BY 
     Year, 
     Month, 
     Day, 
     Hour 
)

来源

2014-06-11 08:21:09 Ambrish

downvote的原因是？ – Ambrish

尝试使用此代码时出现无效的语法错误 – nadG

以下查询会产生运行总数;

WITH Base AS 
    (
     SELECT ROW_NUMBER() OVER (ORDER BY Year, Month, Day, Hour) RowNum, 
    Year, Month, Day, Hour, count(*) as CountPerHour, sum(Total) as TotalPerHour FROM table1 group by Year, Month, Day, Hour 
    ) 
    select T1.Year, T1.Month, T1.Day, T1.Hour, T1.CountPerHour, sum(T2.TotalPerHour) from BASE as T1 
    join BASE as T2 on T2.RowNum <= T1.RowNum 
    Group by T1.Year, T1.Month, T1.Day, T1.Hour, T1.CountPerHour

来源

2014-06-11 09:19:10 Vijred

通常，数据库应优化此查询，所以它不应该是一个问题来算两次：

select Hour, count(*) TotalPerHOur, sum(count(*)) TotalCumulative 
from table1 
group by Year, Month, Day, Hour

来源

2014-06-11 11:26:24 brummfondel

SQL运行总数从一个计数

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