通过POPEN执行的模块

Question

林执行的模块和popen1.py的呼叫popen2.py使用子模块，

但popen2.py的输出是不是被displayed..When我显示子进程id ，它是displayed..Where输出是否会被打印，popen2.py

呼叫

child = subprocess.Popen(['python', 'popen2.py',"parm1='test'","parm='test1'"], shell=True, 
         stdin=subprocess.PIPE, 
         stdout=subprocess.PIPE, stderr=subprocess.PIPE) 

Answer 1

过程完成后，你可以阅读child.stdout和child.stderr获取数据（因为你通过subprocess.PIPE）

或者，您可以使用oudata,errdata = child.communicate()，它将等待子流程完成，然后将其输出为字符串。

---

从设计的角度来看，最好导入。我将重构popen2.py如下：

#popen2.py 
# ... stuff here 
def run(*argv): 
    #... 

if __name__ == '__main__': 
    import sys 
    run(sys.argv[1:]) 

然后，你可以导入和运行popen1.py popen2.py：

#popen1.py 
import popen2 
popen2.run("parm1=test","parm=test1") 

Answer 2

您可以使用child.stdout/child.stdin与以comunicate进程：

child = subprocess.Popen(['python', 'popen2.py',"parm1='test'","parm='test1'"], shell=True, 
        stdin=subprocess.PIPE, 
        stdout=subprocess.PIPE, stderr=subprocess.PIPE) 
print child.stdout.readlines()