ORACLE SQL得到2个select语句

Question

检索两个值的差异，我们有2个非常简单的SELECT语句：

SELECT value from table where date between DATE1 and DATE2 
SELECT value from table where date between DATE3 and DATE4 

我们需要一种方法来写一个SQL语句，将获得“价值”的区别这是从这两个SQL语句返回的。

我们试过以下，但没有成功：

SELECT value from table where date between DATE1 and DATE2 
minus 
SELECT value from table where date between DATE3 and DATE4 

任何建议高度赞赏。

Answer 1

未经测试，但应该工作：

SELECT 
    (SELECT value from table where date between DATE1 and DATE2) - 
    (SELECT value from table where date between DATE3 and DATE4) 
FROM dual; 

假设你SELECT value是保证返回一个值

Answer 2

SELECT value FROM TBL WHERE date BETWEEN DATE1 and DATE2 
AND value NOT IN (SELECT value FROM TBL WHERE date BETWEEN DATE3 AND DATE4) 

Answer 3

请试试这个：

SET SERVEROUTPUT ON 
DECLARE 
V_FIRST NUMBER := 0; 
V_SECOND NUMBER := 0; 
BEGIN 
    SELECT value into V_FIRST from table where rownum=1 and date between DATE1 and DATE2; 
    SELECT value into V_SECOND from table where rownum=1 and date between DATE3 and DATE4; 

    DBMS_OUTPUT.PUT_LINE (V_FIRST-V_SECOND); 
END; 

Answer 4

(
SELECT value from table where date between DATE1 and DATE2 
minus 
SELECT value from table where date between DATE3 and DATE4 
) 
union all 
(
SELECT value from table where date between DATE3 and DATE4 
minus 
SELECT value from table where date between DATE1 and DATE2 
) 

Answer 5

下面的语句笑对于你的情况ULD工作

(
SELECT value from table where date between DATE3 and DATE4 
minus 
SELECT value from table where date between DATE1 and DATE2 
) 
union 
(
SELECT value from table where date between DATE1 and DATE2 
minus 
SELECT value from table where date between DATE3 and DATE4 
) 

Answer 6

如果你觉得你内心的疑问可以给多个值，使用下面

SELECT 
(SELECT sum(value) from table where date between DATE1 and DATE2) - 
(SELECT sum(value) from table where date between DATE3 and DATE4) as answer 

FROM DUAL;