2014-02-13 63 views
0

所以我试图使用[RKObjectManager postObject:path:parameters:success:failure:],但在使用我的登录POST请求时遇到了一些麻烦。出于某种原因,我一直从我的服务器说,所需要的电子邮件和密码参数得到响应回来,即使我通过下面的字典中的参数:无法获得RestKit 0.2到POST参数

NSDictionary *params = @{@"email": @"[email protected], @"password": @"test123!"};

当我注销RKObjectRequestOperation它没有在请求中显示任何参数。我是否必须在请求中传递一个对象?如果是这样,我会传入什么对象? (之前我只是使用和AFJSONRequestOperation,但我想更新应用程序以使用RestKit并利用它提供的简单对象映射)。

任何帮助,将不胜感激。

编辑与更多的代码:

我有RKObjectManager的子类,称为UserAuthService,使用RKMIMETYPEJSON作为requestSerializationMIMEType,与下面的请求描述符设置:

// User 
RKResponseDescriptor *userResponseDescriptor = [RKResponseDescriptor responseDescriptorWithMapping:[UserAuthMappingProvider userMapping] 
                            method:RKRequestMethodPOST 
                           pathPattern:@"user/login" 
                            keyPath:@"response.users" 
                           statusCodes:RKStatusCodeIndexSetForClass(RKStatusCodeClassSuccessful)]; 
[self addResponseDescriptor:userResponseDescriptor]; 

的方法我用实际要求是:

- (void)logUserInWithEmail:(NSString *)email andPassword:(NSString *)password success:(void (^)(UserObject *))success failure:(void (^)(RKObjectRequestOperation *, NSError *))failure 
{ 
// Request Params 
NSDictionary *params = @{@"email": email, @"password": password}; 
NSLog(@"Params: %@", params); 


[self postObject:nil path:@"user/login" parameters:params 
     success:^(RKObjectRequestOperation *operation, RKMappingResult *mappingResult){ 
      if (success) 
      { 
       NSArray *userArray = [mappingResult array]; 
       success([userArray firstObject]); 
      } 

     } 
     failure:^(RKObjectRequestOperation *operation, NSError *error){ 
      NSLog(@"Error: %@", error); 

      if (failure) 
      { 
       failure(operation, error); 
      } 
     }]; 
} 

在UserAuthMappingProvider的userMapping方法看起来像这样:

+ (RKEntityMapping *)userMapping 
{ 
    AppDelegate *appDelegate = (AppDelegate *)[[UIApplication sharedApplication] delegate]; 

    RKEntityMapping *userMapping = [RKEntityMapping mappingForEntityForName:@"User" inManagedObjectStore:appDelegate.managedObjectStore]; 
    userMapping.identificationAttributes = @[ @"uuid" ]; 

    [userMapping addAttributeMappingsFromDictionary:@{@"email": @"email", 
                 @"first_name": @"firstName", 
                 @"last_name": @"lastName", 
                 @"is_logged_in": @"isLoggedIn", 
                 @"site_id": @"siteID", 
                 @"user_name": @"username", 
                 @"uuid": @"uuid"}]; 
    return userMapping; 
} 

和UserObject(每一组中.M到@dynamic):

@interface UserObject : NSManagedObject 

@property (strong, nonatomic) NSString *email; 
@property (strong, nonatomic) NSString *firstName; 
@property (strong, nonatomic) NSString *lastName; 
@property (assign, nonatomic) BOOL isLoggedIn; 
@property (strong, nonatomic) NSNumber *siteID; 
@property (strong, nonatomic) NSString *username; 
@property (strong, nonatomic) NSString *uuid; 

@end 

错误我收到的回复是:

Error Domain=org.restkit.RestKit.ErrorDomain Code=-1011 "Expected status code in (200-299), got 400" UserInfo=0x8eadbf0 {NSLocalizedRecoverySuggestion={"required_parameters":{"email":"string","password":"string"},"status":"failed","message":"Insufficient information passed. see 'required_parameters'"} 

基本上我的目标是获取用户/登录调用的成功响应并将其映射到UserObject。

+0

您需要提供一个对象(与关联的路由)或路径。显示一些代码。使用Charles查看它发送的内容。说明服务器的期望。你设置了什么序列化类型? – Wain

+0

我在上面添加了一些代码,希望有所帮助。 – sfeuerstein

+0

您可以配置restkit网络日志记录以获取更多详细信息:'RKLogConfigureByName(“RestKit/Network *”,RKLogLevelTrace);' – vokilam

回答

1

最后弄明白了,当然这是一个非常愚蠢的问题。服务器期待一个params字典,但我的对象管理器的requestSerializationMIMEType被设置为RKMIMETypeJSON。所以,一旦我评论说,请求行为良好,对象为零,参数设置为字典@{@"email": email, @"password": password}