Scala：实现数字的子类型[T]

Question

如何实现数字[T]的子类型？ 我一直在寻找指导，但没有找到任何。 子类型的例子可能是理性的还是复杂的？

在此先感谢 特勒尔斯

Answer 1

一个绝对无用串数字：

trait StringIsNumeric extends Numeric[String] { 
    def plus(x: String, y: String): String = "%s+%s" format (x, y) 
    def minus(x: String, y: String): String = "%s-%s" format (x) 
    def times(x: String, y: String): String = "%s*%s" format (x, y) 
    def quot(x: String, y: String): String = "%s/%s" format (x, y) 
    def rem(x: String, y: String): String = "%s%%s" format (x, y) 
    def negate(x: String): String = "-%s" format (x) 
    def fromInt(x: Int): String = x.toString 
    def toInt(x: String): Int = 0 
    def toLong(x: String): Long = 0L 
    def toFloat(x: String): Float = 0.0f 
    def toDouble(x: String): Double = 0.0 
} 
implicit object StringIsNumeric extends StringIsNumeric with Ordering.StringOrdering 


def x[T: Numeric](t1 : T, t2 : T) = { 
    val n = implicitly[Numeric[T]] 
    import n._ 
    t1 * t2 
} 
scala> x("a","b") 
res0: java.lang.String = a*b 

Answer 2

我加Real到Scalaz，用实例Real[Double]和Real[Dual]。

我认为很方便，使fromDouble隐含