ClassNotFoundException和ActionbarSherlock SearchView

Question

我目前在Android应用程序中实现了ActionbarSherlock的4.2.0版本。 而我在使用SearchView小部件时遇到问题。

我目前已经实现了这样的小部件：

import com.actionbarsherlock.app.ActionBar.Tab; 
import com.actionbarsherlock.app.SherlockFragmentActivity; 
import com.actionbarsherlock.view.Menu; 
import com.actionbarsherlock.view.MenuItem; 
import com.actionbarsherlock.widget.SearchView; 
import com.actionbarsherlock.widget.SearchView.OnQueryTextListener; 

public class MainActivity extends SherlockFragmentActivity 
{ 

    /*...*/ 


    @Override 
    public boolean onCreateOptionsMenu(Menu menu) { 
     SearchView searchView = new SearchView(getSupportActionBar().getThemedContext()); 
     searchView.setQueryHint(getResources().getString(R.string.searchHint_Label)); 
     searchView.setIconifiedByDefault(true); 
     searchView.setOnQueryTextListener(new OnQueryTextListener(){ 

      @Override 
      public boolean onQueryTextSubmit(String query) { 
       // Do stuff 
      } 

      @Override 
      public boolean onQueryTextChange(String newText) { 
       // TODO Auto-generated method stub 
       return false; 
      } 

     }); 

     menu.add("Search") 
      .setIcon(R.drawable.abs__ic_search) 
      .setActionView(searchView) 
      .setShowAsAction(MenuItem.SHOW_AS_ACTION_IF_ROOM | MenuItem.SHOW_AS_ACTION_COLLAPSE_ACTION_VIEW); 

     return true; 
    } 
} 

现在，每当我开始调试应用程序我碰到下面的错误在搜索查看的构造函数：

01-01 11:46:40.365: E/dalvikvm(1385): Could not find class 'com.actionbarsherlock.widget.SearchView$11', referenced from method com.actionbarsherlock.widget.SearchView.<init> 
Call Stack: 
Thread [<1> main] (Suspended (exception ClassNotFoundException))  
    <VM does not provide monitor information> 
    PathClassLoader.findClass(String) line: 240 
    PathClassLoader(ClassLoader).loadClass(String, boolean) line: 551 
    PathClassLoader(ClassLoader).loadClass(String) line: 511  
    DexFile.defineClass(String, ClassLoader, int, ProtectionDomain) line: not available [native method] 
    DexFile.loadClassBinaryName(String, ClassLoader) line: 207 
    PathClassLoader.findClass(String) line: 200 
    PathClassLoader(ClassLoader).loadClass(String, boolean) line: 551 
    PathClassLoader(ClassLoader).loadClass(String) line: 511  
    MainActivity.onCreateOptionsMenu(Menu) line: 124  
    MainActivity(Watson).onCreatePanelMenu(int, Menu) line: 45 
    ActionBarSherlockCompat(ActionBarSherlock).callbackCreateOptionsMenu(Menu) line: 559  
    ActionBarSherlockCompat.preparePanel() line: 479  
    ActionBarSherlockCompat.dispatchInvalidateOptionsMenu() line: 272 
    ActionBarSherlockCompat$1.run() line: 984 
    ViewRoot(Handler).handleCallback(Message) line: 587 
    ViewRoot(Handler).dispatchMessage(Message) line: 92 
    Looper.loop() line: 130 
    ActivityThread.main(String[]) line: 3683  
    Method.invokeNative(Object, Object[], Class, Class[], Class, int, boolean) line: not available [native method] 
    Method.invoke(Object, Object...) line: 507 
    ZygoteInit$MethodAndArgsCaller.run() line: 839 
    ZygoteInit.main(String[]) line: 597 
    NativeStart.main(String[]) line: not available [native method] 

内出现此错误我使用应用程序支持的所有Android版本（2.2 - 4.2） 在发生此异常之后恢复调试时，应用程序运行良好，SearchView也可以正常工作，但我仍然在想为什么发生此异常。

Answer 1

请使用此方法以XML创建菜单：

<?xml version="1.0" encoding="utf-8"?> 
<menu xmlns:android="http://schemas.android.com/apk/res/android" >  
<item 
    android:id="@+id/search"  
    android:icon="@drawable/abs__ic_search"  
    android:showAsAction="add here your action" 
    android:title="@string/search"> 
</item> 
</menu> 

在活动

@Override 
public boolean onCreateOptionsMenu(Menu menu) { 
    MenuInflater inflater = getSupportMenuInflater(); 
    inflater.inflate(R.menu.menu, menu); 
    return true; 
} 



@Override 
public boolean onOptionsItemSelected(MenuItem item) { 
    switch (item.getItemId()) { 
    case R.id.search: 
     add code here 
     return true; 
    default: 
     return super.onOptionsItemSelected(item); 
    } 
}