为什么它在开始收听之前不睡3秒钟？

Question

我想要做的事：

1. 执行TextToSpeech
2. SpeechRecognizer开始监听作为用户重复 TextToSpeech'd词/短语

但我的问题是，例如，如果我通过TextToSpeech说“example”，那么当SpeechRecognizer开始收听时，它也会从之前的“示例”中获取并添加到用户所说的“示例”中。最后，我结束了“示例”，这是我不想要的。

代码：

public void onItemClick(AdapterView<?> parent, View view, int position, 
     long id) { 
    // TODO Auto-generated method stub 
    item = (String) parent.getItemAtPosition(position); 
    tts.speak(item, TextToSpeech.QUEUE_FLUSH, null); 
    Thread thread = new Thread() { 
     public void run() { 
      try { 
       sleep(3000); 
      } catch (InterruptedException e) { 
       e.printStackTrace(); 
      } 
     } 
    }; 
    thread.start(); 
    sr.startListening(srIntent); 
} 

Answer 1

你正在做的两种工艺在两个线程中。您正在创建线程并使其在3秒内休眠，并在独立的UI线程中启动sr.startListening(srIntent); Intent。所以它马上启动Intent。同时使用过程中的一个线程像我张贴下面

public void onItemClick(AdapterView<?> parent, View view, int position, 
    long id) { 
// TODO Auto-generated method stub 
item = (String) parent.getItemAtPosition(position); 
tts.speak(item, TextToSpeech.QUEUE_FLUSH, null); 
Thread thread = new Thread() { 
    public void run() { 
     try { 
      sleep(3000); 
     } catch (InterruptedException e) { 
      e.printStackTrace(); 
     } 
    mSpeech.sendEmptyMessage(0); 
    } 
}; 
thread.start(); 

}

创建一个内部处理程序类来执行UI操作

private Handler mSpeech=new Handler(){ 
    public void handleMessage(android.os.Message msg) { 
     sr.startListening(srIntent); 
    } 
}; 

Answer 2

它必须是run()体

public void onItemClick(AdapterView<?> parent, View view, int position, 
     long id) { 
    // TODO Auto-generated method stub 
    item = (String) parent.getItemAtPosition(position); 
    tts.speak(item, TextToSpeech.QUEUE_FLUSH, null); 
    Thread thread = new Thread() { 
     public void run() { 
      try { 
       sleep(3000); 
      } catch (InterruptedException e) { 
       e.printStackTrace(); 
      } 
      sr.startListening(srIntent); 
     } 
    }; 
    thread.start(); 

}