6
我试图用ajax发送请求,但有状态400错误请求。 我应该发送什么样的数据以及如何在控制器中获取数据? 我敢肯定,要求是精唯一参数出错如何在Spring框架中使用参数发送和接收ajax请求?
JSP
<script type="text/javascript">
var SubmitRequest = function(){
$.ajax({
url : "submit.htm",
data: document.getElementById('inputUrl'),
type: "POST",
dataType: "text",
contentType: false,
processData: false,
success :
function(response) {
$('#response').html(response);
}
});
}
</script>
控制器
@RequestMapping(value = "/submit", method = RequestMethod.POST)
public @ResponseBody
String Submit(@RequestParam String request) {
APIConnection connect = new APIConnection();
String resp = "";
try {
resp = "<textarea rows='10'cols='100'>" + connect.doConnection(request) + "</textarea>";
} catch (Exception e) {
// TODO Auto-generated catch block
resp = "<textarea rows='10'cols='100'>" + "Request failed, please try again." + "</textarea>";
}
return resp;
}
谢谢,它的工作原理! – Bboy820602 2014-10-02 09:02:16
不客气,我很乐意为您提供帮助 – Pracede 2014-10-02 10:02:11