MySQL的$ I ++相当于

查询我使用的是：

SELECT COUNT(*), 
    SUM(amount) AS amount, 
    FROM_UNIXTIME(added, '%W (%e/%m)') AS daily 
FROM affiliates_earnings 
WHERE added >= '1319074836' 
    AND added <= '1319679636' 
GROUP BY daily

输出：

+----------+--------+-------------------+ 
| COUNT(*) | amount | daily    | 
+----------+--------+-------------------+ 
|  1 | 195 | Tuesday (25/10) | 
|  4 | 470 | Wednesday (26/10) | 
+----------+--------+-------------------+

我想显示：

+-------+----------+--------+-------------------+ 
| i  |COUNT(*) | amount | daily    | 
+-------+----------+--------+-------------------+ 
| 1  |  1 | 195 | Tuesday (25/10) | 
| 2  |  4 | 470 | Wednesday (26/10) | 
+-------+----------+--------+-------------------+

本质i将是连续的数字（即1,2,3,4,5,6 ...）。

我该如何做到这一点？

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2011-10-27 Meisam Mulla

去做这个？从记录集中拉出时在目标环境中迭代。 –

检查此贴：http://stackoverflow.com/questions/304461/generate-an-integer-sequence-in-mysql – Raihan

@ TomalakGeret'kal我想要生成一些flot图表。 –

没有ROW_NUMBER（），您可以伪造它per this answer或this one：

SELECT @i := @i + 1 AS i, COUNT(*), ... 
    FROM affiliates_earnings 
    JOIN (SELECT @i := 0) dummy 
    WHERE ... 
GROUP BY ...;

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2011-10-27 02:23:21 pilcrow

SELECT @i：= @i + 1 ** as i **，... – Bohemian

@Bohemian，挺对的。更新。 – pilcrow

这样做几乎是废话，但如果你真的想，尝试这样的：你为什么要

SELECT 
    @i:[email protected]+1 as i, 
    COUNT(*), 
    SUM(a.amount) AS amount, 
    FROM_UNIXTIME(a.added, '%W (%e/%m)') AS daily 
FROM affiliates_earnings a, (SELECT @i:=0) b 
WHERE a.added >= '1319074836' 
    AND a.added <= '1319679636' 
GROUP BY a.daily

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2011-10-27 02:25:41 xdazz

MySQL的$ I ++相当于

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