2016-06-18 173 views
0

作为较大的SQL查询的一部分,我创建了一个临时表来存储来自另一个(临时)表的相关项目。 insert语句的select部分使用CASE语句来填充最后一列(labSample),其中基于dataSource列的值为1或0。 SSMS在labSample列中返回无效列错误,以引用dataSource。我不能为我的生活找出这个错误发生的原因 - 这是一个语法错误还是我错过了什么?SQL Server 2008 CASE语句提供了无效的列错误

以下使用的命名规则是列名前述下划线处于#related表中的新列,同时没有下划线的列名在#temp_trace表起源(除了dataSourcelabSample列,其仅在#related表)。

我真的很感谢这个帮助!

create table #related (_tr_id int, _mp_id int, _sta_id int, _tr_number_s nvarchar(20), 
    _tr_tstamp_ts datetime, _tr_team_s nvarchar(100), _tr_comment_s nvarchar(512), 
    _kld_id_medium int, _kld_id_reason int, _kld_id_typeofsmpl int, _sp_id int, 
    _sa_id int, _sa_depth_fl float, _fr_number_l int, dataSource nvarchar(128), labSample bit) 

insert into #related (_tr_id, _mp_id, _sta_id, _tr_number_s, 
    _tr_tstamp_ts, _tr_team_s, _tr_comment_s, 
    _kld_id_medium, _kld_id_reason, _kld_id_typeofsmpl, _sp_id, _sa_id, _sa_depth_fl, 
    _fr_number_l, dataSource, labSample) 
select 
    tt.tr_id as _tr_id, 
    tt.mp_id as _mp_id, 
    tt.sta_id as _sta_id, 
    tt.tr_number_s as _tr_number_s, 
    tt.tr_tstamp_ts as _tr_tstamp_ts, 
    tt.tr_team_s as _tr_team_s, 
    tt.tr_comment_s as _tr_comment_s, 
    tt.kld_id_medium as _kld_id_medium, 
    tt.kld_id_reason as _kld_id_reason, 
    tt.kld_id_typeofsmpl as _kld_id_typeofsmpl, 
    sp.sp_id as _sp_id, 
    sa.sa_id as _sa_id, 
    sa.sa_depth_fl as _sa_depth_fl, 
    fr.fr_number_l as _fr_number_l, 
    kd.kld_value_s as dataSource, 
    case dataSource 
     when 'Field' then 0 
     when 'Unknown' then 0 
     else 1 
    end 
from #temp_trace tt 
    inner join spot sp on sp.tr_id = tt.tr_id 
    inner join sample sa on sa.sp_id = sp.sp_id 
    inner join fraction fr on fr.sa_id = sa.sa_id 
    inner join kld_data kd on kd.kld_id = fr.kld_id_datasource 
where mp_id = @tr_mp_id and 
    sta_id = @tr_sta_id and 
    CAST(tr_tstamp_ts as DATE) = CAST(@tr_tstamp_ts as DATE) 

回答

2

据我所知,dataSource不是任何连接表中的列名称。它实际上是kd.kld_value_s的别名。你需要改变你的情况,如下所示:

case kd.kld_value_s 
    when 'Field' then 0 
    when 'Unknown' then 0 
    else 1 
end 
+0

谢谢@Mahedi。像魅力一样工作。我认为,因为我已经在'#related'表中声明了'dataSource'作为列,所以我可以从case语句中访问它,但显然我错了! –

0

尝试follwing。它可能会帮助你

CASE WHEN kd.kld_value_s = 'Field' THEN 0 
     WHEN kd.kld_value_s = 'Unknown' THEN 0 
     ELSE 1 
END AS dataSource