检查一个NSDate是否在本周使用当周

Question

我想检查一个NSDate是否与今天在同一周。所以我认为weekOfYear从NSDateComponents s就像这post中提到的。

- (BOOL)dateIsThisWeek:(NSDate *)date 
{ 
    NSCalendar *cal = [NSCalendar currentCalendar]; 
    [cal setFirstWeekday: 2]; // Added in second try 

    NSDate *today = [NSDate date]; 
    NSDateComponents *todaysComponents = [cal components:NSCalendarUnitWeekOfYear fromDate: today]; 
    NSUInteger todaysWeek = [todaysComponents weekOfYear]; 

    NSDateComponents *otherComponents = [cal components:NSCalendarUnitWeekOfYear fromDate: date]; 
    NSUInteger anotherWeek = [otherComponents weekOfYear]; 

    return todaysWeek == anotherWeek; // todaysWeek=7 | anotherWeek=8 
} 

在我的例子中，我的日期如下：

today: 2017-02-15 12:00:00 +0000 
date: 2017-02-18 12:00:00 +0000 

的问题是，todaysWeek被设定为7和anotherWeek〜8，我不能想象为什么。

我认为这个问题可能是，该周开始在周日，所以我的日历的首个工作日设置为2（星期一），可惜没有成功。

UPDATE

我也试过这个代码，但不幸的是同样的结果：

NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian]; 
NSDateComponents *todaysComponents = [gregorian components:NSCalendarUnitWeekOfYear fromDate:[NSDate date]]; 
NSUInteger todaysWeek = [todaysComponents weekOfYear]; 
NSDateComponents *otherComponents = [gregorian components:NSCalendarUnitWeekOfYear fromDate: date]; 
NSUInteger datesWeek = [otherComponents weekOfYear]; 

return todaysWeek==datesWeek; // todaysWeek=7 | datesWeek=8 

两个日期应该是在一周7号一样多websites的描述。

Answer 1

试试这个也许？ （从我自己的项目代码复制）

NSCalendar *gregorianCalendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian]; 
[gregorianCalendar setLocale:[NSLocale localeWithLocaleIdentifier:@"be_NL"]]; 

NSDateComponents *comps = [[NSDateComponents alloc] init]; 
[comps setDay:19]; 
[comps setMonth:02]; 
[comps setYear:2017]; 
NSDate *date = [gregorianCalendar dateFromComponents:comps]; 

//NSCalendar *cal = [NSCalendar currentCalendar]; 
//[gregorianCalendar setFirstWeekday:2]; // Added in second try 

NSDate *today = [NSDate date]; 
NSDateComponents *todaysComponents = [gregorianCalendar components:NSCalendarUnitWeekOfYear fromDate: today]; 
//[todaysComponents setWeekdayOrdinal:2]; 

NSDateComponents *otherComponents = [gregorianCalendar components:NSCalendarUnitWeekOfYear fromDate: date]; 
//[otherComponents setWeekdayOrdinal:2]; 

// Not sure if needed to set timezone too depending on your local time, but you can set this for all dates if needed 
//[otherComponents setTimeZone:[NSTimeZone localTimeZone]]; 

NSUInteger todaysWeek = [todaysComponents weekOfYear]; 
NSUInteger anotherWeek = [otherComponents weekOfYear]; 

NSLog(@"todays week %ld",(long)todaysWeek); 
NSLog(@"anotherWeek %ld",(long)anotherWeek); 

打印出：

2017-02-17 03:51:58.231797 Sneak[5518:2676264] todays week 7 
2017-02-17 03:51:58.231836 Sneak[5518:2676264] anotherWeek 7 

编辑：（正如在评论部分下面提到）

周一是本星期的第一天达到国际标准ISO 8601，但在美国，加拿大和日本，它算作一周的第二天。星期一是在星期天之前和星期二之前在我们现代的格里历日历中。 - timeanddate.com/calendar/days/monday.html希望 “be_NL” 永不开关 - DonMag

Answer 2

这是一个非常轻微修改潜行的代码......与调用它：

// 
// startDayOfWeek: Sunday == 1, Monday == 2, Tues == 3, etc 

Bool b = [self dateIsThisWeek:date startDayOfWeek:2]; 


- (BOOL)dateIsThisWeek:(NSDate *)dateToTest startDayOfWeek:(NSInteger)iStart { 

    NSCalendar *gregorianCalendar = [[NSCalendar alloc] initWithCalendarIdentifier:NSCalendarIdentifierGregorian]; 

    // this is the key - 1 == week runs Sunday-Saturday, 2 == Monday-Sunday, 3 == Tues-Mon, etc 
    [gregorianCalendar setFirstWeekday:iStart]; 

    NSDate *today = [NSDate date]; 

    NSDateComponents *todaysComponents = [gregorianCalendar components:NSCalendarUnitWeekOfYear|NSCalendarUnitWeekday fromDate: today]; 
    NSInteger todaysWeek = [todaysComponents weekOfYear]; 

    NSDateComponents *testComponents = [gregorianCalendar components:NSCalendarUnitWeekOfYear|NSCalendarUnitWeekday fromDate: dateToTest]; 
    NSInteger testsWeek = [testComponents weekOfYear]; 

    return todaysWeek == testsWeek; 
}