选择最大或最小结果

Question

我有一个查询，一直给我麻烦。我认为可能有一个简单的解决方案，但请尽可能帮助我！

我的主要问题是，通常每个cust_id有多个电子邮件。有唯一的标识符，如序列号（seq_no）和更新日期（updated_date）。我只想要为任何一个客户展示最新的电子邮件地址。

顺便说一下，这是一个oracle数据库。

有什么建议吗？

SELECT DISTINCT 
table1.indident_id, 
table1.incident_detail_id, 
table1.incdent_entered_date, 
table1.entering_employee, 
table2.EMAIL 
FROM table1 
left outer join table2 on table1.cust_id=table2.cust_id 
WHERE table1.incdent_entered_date>=current_date-4 
AND table1.table1.incident_detail_id=(select min(table1.table1.incident_detail_id)from table1) 
AND table2.EMAIL NOT IN ('NONE','none','none@none.com') 
AND table2.EMAIL like '%@%' 

Answer 1

有几个选项。最有效的是使用分析功能。

SELECT * 
    FROM (
    SELECT table1.indident_id, 
      table1.incident_detail_id, 
      table1.incdent_entered_date, 
      table1.entering_employee, 
      table2.EMAIL, 
      row_number() over (partition by table2.cust_id 
            order by table2.updated_date desc) rnk 
     FROM table1 
      left outer join table2 on table1.cust_id=table2.cust_id 
    WHERE table1.incdent_entered_date>=current_date-4 
     AND table1.table1.incident_detail_id=(select min(table1.table1.incident_detail_id) 
               from table1) 
     AND table2.EMAIL NOT IN ('NONE','none','none@none.com') 
     AND table2.EMAIL like '%@%' 
) 
WHERE rnk = 1 

效率较低，但东西，将工作在几乎任何数据库，将做类似的东西你目前与incident_detail_id子查询

SELECT table1.indident_id, 
      table1.incident_detail_id, 
      table1.incdent_entered_date, 
      table1.entering_employee, 
      table2.EMAIL 
     FROM table1 
      left outer join table2 on table1.cust_id=table2.cust_id 
    WHERE table1.incdent_entered_date>=current_date-4 
     AND table1.table1.incident_detail_id=(select min(table1.table1.incident_detail_id) 
               from table1) 
     AND table2.update_date = (SELECT MAX(t2_inner.update_date) 
            FROM table2 t2_inner 
            WHERE t2_inner.cust_id = table1.cust_id) 
     AND table2.EMAIL NOT IN ('NONE','none','none@none.com') 
     AND table2.EMAIL like '%@%'