2012-03-22 70 views
-1

嗨,我尝试以下选择:当组属性设置,用户必须成为会员:Hibernate的情况下,Where语句

FROM Appointment a WHERE (CASE WHEN a.group!=null THEN :user MEMBER OF a.group.groupMembers ELSE true END) 

,但我得到:

org.hibernate.hql.ast.QuerySyntaxException: unexpected token: MEMBER near line 1, column 88 [FROM de.lyth.appointment.model.Appointment a WHERE (CASE when a.group!=null THEN :user MEMBER OF a.group.groupMembers ELSE true END) ] 

怎么能我这样做?

感谢

编辑: 我解决它通过改变为:

(a.group==null OR :user MEMBER OF a.group.groupMembers) 
+0

添加您的解决方案作为答案并接受它。 – ManuPK 2012-03-22 13:48:51

+0

对不起,我没有足够的声誉 – wutzebaer 2012-03-22 14:03:20

回答

-1

我解决它通过改变为: (a.group == null或:a.group用户成员。 groupMembers)

+1

那么这是否意味着什么时候不支持hql where子句? – 2016-02-17 20:17:14