如何使用AJAX PHP和mysqli的,而无需使用任何按钮,开始读数据库 数据Ajax功能? 当我向表中添加一行时,我希望在页面上显示信息而不加载/刷新页面或单击按钮。我可以这样做吗?实现使用的mysqli和PHP和jQuery
而这个信息将出现如下图所示
PHP代码
<?php
if (isset($_GET['id'])) {
$id = intval($_GET['id']);
$date = date("l jS \of F Y");
$query = mysqli_query($conn, "select * from tbl_dailyprogress where db_activityid='$id' and db_d='1'")or die(mysqli_error($conn));
$count = mysqli_num_rows($query);
if ($count != 0) {
echo"<table class='ol-md-12 table-bordered table-striped table-condensed cf table-bordered' id='alternatecolor'>";
echo"<thead class='cf'>";
echo"<tr>";
echo" <th style='background:#f7ac01;font-size:16px;vertical-align: middle;text-align:center'rowspan='2' >Date</th>
<th style='background:#f7ac01;font-size:16px;vertical-align: middle;text-align:center'rowspan='2' >Notes</th>
<th style='background:#f7ac01;font-size:16px;vertical-align: middle;text-align:center'rowspan='2' >Progress %</th>
";
echo"</tr></thead><tbody>";
while ($row = mysqli_fetch_array($query)) {
$idp = $row['db_id'];
$date = $row['db_date'];
$note = $row['db_note'];
$progress = $row['db_progress'];
echo"<tr>";
echo"<td data-title='Date'>";
echo $date;
echo"</td>";
echo"<td data-title='Note'>";
echo $note;
echo"</td>";
echo"<td data-title='Progress %'>";
echo'
<div class="progress">
<div class="progress-bar" role="progressbar" aria-valuenow="70" aria-valuemin="0" aria-valuemax="100" style="width:' . $progress . '%">
' . $progress . '%
</div>
</div>';
echo"</td>";
}
echo"</tr></tbody>";
echo"</table>";
echo"<br/>";
}?>
使用jQuery阿贾克斯 – Deep
我不知道你的意思。你想要在用户添加行时自动添加行?如果用户在浏览器中添加一行,为什么需要查询数据库获取更多行?您已在浏览器中拥有新行。 – BeetleJuice
我该怎么办,我没有与经验,如果你能帮助我PLZ – user3018000