'app.routing.ts'文件如何使用角度4中的路由正确导航页面?
import { NgModule } from '@angular/core';
import { Routes, RouterModule } from '@angular/router';
//Layouts
import { FullLayoutComponent } from './layouts/full-layout.component';
//pages
import { DashboardComponent } from './pages/dashboard.component'
import { UploadFileComponent } from './pages/UploadFile.component'
export const routes: Routes = [
{
path: '',
redirectTo: 'full-layout',
pathMatch: 'full',
},
{
path: '',
component: FullLayoutComponent,
data: {
title: 'Dashboard'
}
},
{
path: 'UploadFile',
component: UploadFileComponent,
data: {
title: 'UploadFile'
}
},
];
@NgModule({
imports: [ RouterModule.forRoot(routes) ],
exports: [ RouterModule ]
})
export class AppRoutingModule {}
'全layout.component.html'文件
<a class="nav-link" routerLinkActive="active" [routerLink]="['UploadFile']">
<i class="icon-star"></i> Upload
</a>
我想通过单击链接重定向到UploadFile.component.html
。尽管此重定向正在工作,但是此页面中未加载布局(主页),因此我认为它仅在此页面上重定向。我从侧栏菜单中引用此页面,但在重定向显示后,只会打开“UploadFile”页面,但它不会在此页面中加载布局。
仍然不工作.. – LGB
您使用小写路线?路径:'uploadfile'和routerLink =“/ uploadfile” – FierceDev
在你的问题中添加UploadFileComponent ts代码 – FierceDev