0
我想要做的多内容替换一行在下列文件中的Linux ed编辑:Linux的ed编辑多个搜索/替换一行
#device device mount FS fsck mount mount
#to mount to fsck point type pass at boot options
#
#/dev/dsk/c0d0s2 /dev/rdsk/c0d0s2 /usr ufs 1 yes -
fd - /dev/fd fd - no -
/proc - /proc proc - no -
/dev/dsk/c0d0s3 - - swap - no -
/dev/dsk/c0d0s0 /dev/rdsk/c0d0s0 / ufs 1 no -
/dev/dsk/c0d0s4 /dev/rdsk/c0d0s4 /usr ufs 1 no -
/dev/dsk/c0d0s1 /dev/rdsk/c0d0s1 /var ufs 1 yes -
/dev/dsk/c0d0s7 /dev/rdsk/c0d0s7 /export ufs 2 yes -
/dev/dsk/c0d0s5 /dev/rdsk/c0d0s5 /usr/informix ufs 2 yes -
swap - /tmp tmpfs - yes -
我想交换的所有“C0”在的/ dev“C1”/ ....
这里是我的正则表达式,我投入ED:1,\$s/\(\/dev.*\)\(c0\)\(d0s.*\)/\1c1\3/g
导致
#device device mount FS fsck mount mount
#to mount to fsck point type pass at boot options
#
#/dev/dsk/c0d0s2 /dev/rdsk/c1d0s2 /usr ufs 1 yes -
fd - /dev/fd fd - no -
/proc - /proc proc - no -
/dev/dsk/c1d0s3 - - swap - no -
/dev/dsk/c0d0s0 /dev/rdsk/c1d0s0 / ufs 1 no -
/dev/dsk/c0d0s4 /dev/rdsk/c1d0s4 /usr ufs 1 no -
/dev/dsk/c0d0s1 /dev/rdsk/c1d0s1 /var ufs 1 yes -
/dev/dsk/c0d0s7 /dev/rdsk/c1d0s7 /export ufs 2 yes -
/dev/dsk/c0d0s5 /dev/rdsk/c1d0s5 /usr/informix ufs 2 yes -
swap - /tmp tmpfs - yes -
然而,这漫长的正则表达式:
1,\$s/\(\/dev.*\)\(c0\)\(d0s.*\)\(\/dev.*\)\(c0\)\(d0s.*\)/\1c1\3\4c1\6/g
结果在此:
#device device mount FS fsck mount mount
#to mount to fsck point type pass at boot options
#
#/dev/dsk/c1d0s2 /dev/rdsk/c1d0s2 /usr ufs 1 yes -
fd - /dev/fd fd - no -
/proc - /proc proc - no -
/dev/dsk/c0d0s3 - - swap - no -
/dev/dsk/c1d0s0 /dev/rdsk/c1d0s0 / ufs 1 no -
/dev/dsk/c1d0s4 /dev/rdsk/c1d0s4 /usr ufs 1 no -
/dev/dsk/c1d0s1 /dev/rdsk/c1d0s1 /var ufs 1 yes -
/dev/dsk/c1d0s7 /dev/rdsk/c1d0s7 /export ufs 2 yes -
/dev/dsk/c1d0s5 /dev/rdsk/c1d0s5 /usr/informix ufs 2 yes -
swap - /tmp tmpfs - yes -
离开第一 “C0”仍然为 “C0”,因为它不是由搜索字符串发现
所以我得到了一个文件,我在一行中获得了多个搜索结果,但它只替换了一个实例。我知道“全局”标志在文件的第一步中运行,并标记匹配的行。我希望我知道是什么原因引发了这个问题,但是我没有足够的经验知道如何解决这个问题。
干杯您的帮助
请提供包含数据,结果和预期结果的[示例](https://stackoverflow.com/help/mcve)。 – ArturFH