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学说查询子我已经下表:一个一对多的关系
mysql> show columns from Person;
+------------+--------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+------------+--------------+------+-----+---------+-------+
|guid | varchar(255) | NO | PRI | NULL | |
+------------+--------------+------+-----+---------+-------+
mysql> show columns from Person_Func;
+-----------+--------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+-----------+--------------+------+-----+---------+-------+
| Person_id | varchar(255) | NO | PRI | NULL | |
| Func_id | varchar(255) | NO | PRI | NULL | |
+-----------+--------------+------+-----+---------+-------+
mysql> show columns from Func;
+-------------+--------------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+-------------+--------------+------+-----+---------+-------+
| entry | varchar(255) | NO | | NULL | |
| description | varchar(255) | NO | | NULL | |
| Guid | varchar(255) | NO | PRI | NULL | |
+-------------+--------------+------+-----+---------+-------+
Symfony的Person类包含一个一对多的关系Func键(一个人 - 几个funcs中)使用连接表Person_Func。我想查询Person,他有很多Funcs - steve(a,b,c);约翰(a,b,d); ele(b,d) - 我查询(a,b)函数,应该返回steve和john。
现在我只是遍历所有的人和查询功能 - 这是非常非常缓慢。你可以帮我吗?
UPD 我已经成功与
SELECT DISTINCT d1.guid from (select p.guid, f.entry from Person p, Person_Func jt, Func f where p.Guid = jt.person_id and jt.func_id = f.guid and f.entry in ('A', 'B')) as d1,
(select p.guid, f.entry from Person p, Person_Func jt, Func f where p.Guid = jt.person_id and jt.func_id = f.guid and f.entry in ('A', 'B')) as d2
where d1.guid=d2.guid and d1.entry != d2.entry
但我认为这是一个不是一个好主意,是吗?
任何运气找到了这样做的最佳做法? –