1
我有了这个查询:联盟和两个内部联接假列?
SELECT * FROM (
(SELECT ACCOUNTS.INSTALLTIME, ACCOUNTS.HONAME, ACCOUNTS.ADDRESS, ACCOUNTS.CITY, ACCOUNTS.STATE, ACCOUNTS.ZIP, ACCOUNTS.JOBNUMBER, ACCOUNTS.INSTALLDATE, ACCOUNTS.RESULT, ACCOUNTS.NOTES, ACCOUNTS.SMNOTES, technicians.technumber, technicians.boardplacing
FROM ACCOUNTS
INNER JOIN technicians ON ACCOUNTS.INSTALLER = technicians.technumber)
UNION
(SELECT service.servicetime, service.Customername, service.address, service.city, service.state, service.zip, service.ID, service.serviceday, service.result, service.servicenotes, service.board, technicians.technumber, technicians.boardplacing
FROM service
INNER JOIN technicians ON service.technician= technicians.technumber)
) as t WHERE t.INSTALLDATE = '$date' ORDER BY t.boardplacing
有没有什么办法可以让类似的查询:
SELECT * FROM (
(SELECT ACCOUNTS.INSTALLTIME, ACCOUNTS.HONAME, ACCOUNTS.ADDRESS, ACCOUNTS.CITY, ACCOUNTS.STATE, ACCOUNTS.ZIP, ACCOUNTS.JOBNUMBER, ACCOUNTS.INSTALLDATE, ACCOUNTS.RESULT, ACCOUNTS.NOTES, ACCOUNTS.SMNOTES, '' as priority, ACCOUNTS.PAFS, ACCOUNTS.upsell, ACCOUNTS.TERM, ACCOUNTS.MMRUPGRADE, ACCOUNTS.WARRANTY, ACCOUNTS.EFT, technicians.technumber, technicians.boardplacing
FROM ACCOUNTS
INNER JOIN technicians ON ACCOUNTS.INSTALLER = technicians.technumber)
UNION
(SELECT service.servicetime, service.Customername, service.address, service.city, service.state, service.zip, service.ID, service.serviceday, service.result, service.servicenotes, service.board, '', '', '', '', '', '', technicians.technumber, technicians.boardplacing
FROM service
INNER JOIN technicians ON service.technician= technicians.technumber)
) as t WHERE t.INSTALLDATE = '$date' ORDER BY t.boardplacing
基本上我需要在我的工会假列。有没有什么办法可以把连接关掉?还有其他更好的方法来做到这一点吗?
只要联合中的列数匹配,就应该可以工作。 – 2009-10-15 16:21:23
列匹配,但它仍然给我︰ 提供的参数不是一个有效的MySQL结果资源 – mlebrun15 2009-10-15 16:24:45
mysql_error()说什么? – Greg 2009-10-15 16:28:44