获取查询结果的金额范围内同一查询

Question

我有一个查询：

SELECT case 

when Submission__bTracking = 'Phone' then 'Phone' 
when Submission__bTracking = 'Web' then 'Web' 
when Submission__bTracking = 'Email' then 'Email 
when Submission__bTracking = 'Live__bTech__bSupport' then '@ Live Tech Support 
when Submission__bTracking = 'Verbal' then 'Verbal Request' 
when Submission__bTracking = 'Fax__b__f__bform' then 'Fax/Form' 

End as Sub_Tracking, 

COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30 

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1)) 
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP)) 

GROUP BY Submission__bTracking 

产生以下结果：

Sub_Tracking    tickets 
Email      36 
Fax/Form     1 
@ Live Tech Support   18 
Phone      441 
Web       41 

我怎么还生产中所有的门票总和同样的查询？

象下面这样：

Sub_Tracking    tickets 
Email      36 
Fax/Form     1 
@ Live Tech Support   18 
Phone      441 
Web       41 
ALL       537 

感谢您的帮助！

Answer 1

您可以使用UNION，只是在结果集中增加一个行：

YOUR QUERY 

UNION ALL 
select 'ALL' as Sub_Tracking, 
COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30 

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1)) 
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP)) 

Answer 2

你可以做

...previous lines omitted 
GROUP BY Submission__bTracking 
UNION 
SELECT 'ALL' as Sub_Tracking, count(Submission__bTracking) as tickets 
FROM dbo.MASTER30 
WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1)) 
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP)) 

Answer 3

这里有真正的两种选择。一是工会您有另外一个，计算所有的门票，像

SELECT case 

when Submission__bTracking = 'Phone' then 'Phone' 
when Submission__bTracking = 'Web' then 'Web' 
when Submission__bTracking = 'Email' then 'Email 
when Submission__bTracking = 'Live__bTech__bSupport' then '@ Live Tech Support 
when Submission__bTracking = 'Verbal' then 'Verbal Request' 
when Submission__bTracking = 'Fax__b__f__bform' then 'Fax/Form' 

End as Sub_Tracking, 

COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30 

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1)) 
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP)) 

GROUP BY Submission__bTracking 

UNION ALL 

SELECT "All" AS Sub_Tracking, 

COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30 

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1)) 
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP)) 

初始查询另一种选择是WITH ROLLUP使用（如http://dev.mysql.com/doc/refman/5.6/en/group-by-modifiers.html）

这将是这样的：

SELECT case 

when Submission__bTracking = 'Phone' then 'Phone' 
when Submission__bTracking = 'Web' then 'Web' 
when Submission__bTracking = 'Email' then 'Email 
when Submission__bTracking = 'Live__bTech__bSupport' then '@ Live Tech Support 
when Submission__bTracking = 'Verbal' then 'Verbal Request' 
when Submission__bTracking = 'Fax__b__f__bform' then 'Fax/Form' 

End as Sub_Tracking, 

COUNT(Submission__bTracking) as tickets FROM dbo.MASTER30 

WHERE mrSUBMITDATE >= (CONVERT (date, CURRENT_TIMESTAMP -1)) 
AND mrSUBMITDATE < (CONVERT (date, CURRENT_TIMESTAMP)) 

GROUP BY Submission__bTracking WITH ROLLUP 

后来的选项将不输出“ALL”行，但它是短了很多......此外，您不能使用ORDER BY和WITH ROLLUP在一起，所以知道，提前为好。

在这两者之间，我可能会使用第一个选项....这是同由谁回答，但我会使用UNION ALL而不是UNION的其他人提供的两个。这是一个挑剔的细节，但如果你不需要它们，为什么还要重复检查。欲了解更多关于UNION VS UNION ALL，请上网：What is the difference between UNION and UNION ALL?）