提示用户输入正确的输入 - tic tac toe游戏

Question

我正在研究模拟两位玩家之间的tic-tac-toe游戏的程序。这个节目到目前为止是我想要的，除了我要求玩家输入的部分。我想让程序检查（3 x 3）网格是否已经包含一个标记（例如'X'或'o'），并在切换转弯之前继续提示同一个播放器输入正确的输入。以下是我迄今为止：

board = [ 
     0, 1, 2, 
     3, 4, 5, 
     6, 7, 8 
     ] 

def main(): 
    print_instructions() 
    start = str(input("Your game is about to begin. Press 'Q' if you want to quit, or 'K' to proceed: ")) 
    while start != "Q": 
     get_input1() 
     get_input2() 


def display_board(board): 
    print(board[0], "|" , board[1] , "|" , board[2]) 
    print("----------") 
    print(board[3] , "|" , board[4] , "|" , board[5]) 
    print("----------") 
    print(board[6] , "|" , board[7] , "|" , board[8]) 


def print_instructions(): 
    print("Please use the following cell numbers to make your move: ") 
    display_board(board) 


def get_input1(): 
    userInput = input("The first player marks with a 'X'. Type an integer between 0 up to 8 to indiciate where you want to move: ") 
    userInput = int(userInput) 
    if userInput < 0 or userInput > 8 or board[userInput] == "X" or board[userInput] == "o": 
     print("Wrong input! You cannot move there! ") 
    else: 
     board[userInput] = "X" 

    display_board(board) 

def get_input2(): 
    userInput = input("Turn of second player. You mark with a 'o'. Where would you like to move? Type an integer between 0 and 8: ") 
    userInput = int(userInput) 
    if userInput < 0 or userInput > 8 or board[userInput] == "X" or board[userInput] == "o": 
     print("Wrong input! You cannot move there! ") 
    else: 
     board[userInput] = "o" 

    display_board(board) 



main() 

我仍然需要编写该程序决定获胜者是谁的一部分，但我想正确的先拿到def get_input功能。在这种情况下，我如何检查有效输入？我尝试使用while循环，但那只是不停地提示用户而不终止（也许我在那里做了错误）。帮助将不胜感激。

Answer 1

也许你忘了在while循环中输入！ 试试这个。

while userInput < 0 or userInput > 8 or board[userInput] == "X" or board[userInput] == "o": 
    print("Wrong input! You cannot move there! ") 
    userInput = input("Please give a valid move.") 
board[userInput] = "X"