堆栈和堆栈内存存储在C++

Question

我有点困惑我的下面的简单程序的某些成员将获得存储？

#include <iostream> 

using namespace std; 

class Human 
{ 
    public: 
     int *age; //where will it get storage? 
     string *name; //where will it get storage? 

     Human(string name, int age) 
     { 
      this->name = new string; //string will got into heap 
      this->age = new int; //int will go into heap 

      *(this->name) = name; 
      *(this->age) = age; 
     } 

     void display() 
     { 
      cout << "Name : " << *name << " Age : " << *age << endl; 
     } 

     ~Human() 
     { 
      cout << "Freeing memory"; 
      delete(name); 
      delete(age); 
     } 
}; 

int main() 
{ 
    Human *human = new Human("naveen", 24); //human object will go into heap 
    human->display(); 
    delete(human); 
    return 0; 
} 

我创建使用new操作类Human对象。因此，它肯定会在堆中得到存储。但它的属性age和name将在哪里获得存储？

Answer 1

的成员变量age和name它们分别指向int和string将取决于你如何创建Human类的一个对象被存储在堆或堆。

存储在堆栈上：

Human human("naveen", 24); // human object is stored on the stack and thus it's pointer members `age` and `name` are stored on the stack too 

保存在堆上：

Human *human = new Human("naveen", 24); // human object is stored on the heap and thus it's pointer members `age` and `name` are stored on the heap too 

您提供的代码：

Human *human = new Human("naveen", 24); //human object will go into heap 

//human object will go into heap仅仅指Human类的所有成员存储在堆上。