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我有一个ASPX Web窗体,在它的VB代码读取是从名为.rdl一个目录中的文件,然后列出它们作为说一个按钮或超链接等。“报告是本地主机报表服务器上的”Asp.Net,VB,SQL Server Reporting Services ..动态生成的报告从点击查看报告查看器时查看目录?
Protected Sub Page_Load(sender As Object, e As EventArgs) Handles Me.Load
Dim FileLocation As DirectoryInfo = _
New DirectoryInfo("C:\inetpub\wwwroot\Reports")
Dim fi As FileInfo() = FileLocation.GetFiles("*.rdl")
For Each name As FileInfo In fi
' Dim i As Integer
Dim listed As New LinkButton
' listed.Attributes("CssClass") = "a"
' listed.Attributes("Class") = "a"
listed.Attributes("id") = "listed"
listed.Text = (name.Name)
mine.Controls.Add(listed)
'mine.InnerHtml = ""
'i = i + 1
Next
End Sub
另一个有报告查看器。点击报告时,如何将名称/值发送给查看者并重定向到它?
非常感谢您
编辑:我必须做出点击重定向到一个字符串的观众,并有观众使用该字符串,但那么多,从来变异香港专业教育学院怎么试了一下还是错误是
项目'salesreport.rdl'的路径无效。完整路径长度不得超过260个字符;其他限制适用。如果报表服务器处于纯模式,则路径必须以斜线开头。 (rsInvalidItemPath)
这是观众代码
Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load
If Not Page.IsPostBack Then
' Retrieve parameter from Route "Reports/{reportName}"
Dim reportName = Picks.Selecty
'Page.Title = reportName
ReportViewer1.ProcessingMode = ProcessingMode.Remote
Dim serverReport As ServerReport
ServerReport = ReportViewer1.ServerReport
serverReport.ReportServerUrl = New Uri("http://localhost/reportserver/")
serverReport.ReportPath = reportName
' reportName
'
' add parameters here
'Dim param As New ReportParameter("name", "value")
'serverReport.SetParameters(param)
serverReport.Refresh()
End If
End Sub
非常感谢你回答,Prawin..i不太确定你的意思,但我想我的理解,通过在点击时链接它将显示的名称存储到一个字符串中,并将其与查看器一起发送到页面,但是我在那里遇到麻烦了,还有什么帮助?非常感谢,朋友 – minguscoltrane
忘了提及你@Prawin – minguscoltrane