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我在将一些XML反序列化到对象列表时遇到了一些问题,在调试过程中检查DateAndTimeSlot
时总是获得计数0并在该“原始数据”内。将XML反序列化到嵌套对象列表返回计数0
不幸的是我不能改变这些元素的名称。
但是,当检查XML时,我会返回XML中的DateAndTimeslot对象。
与其他对象列表我似乎很好,没有包含名称空间。
我错过了什么?
C#代码:
[XmlRoot("AppointmentAvailabilityStatusResponse")]
public class CheckAppointmentAvailabilityContainer
{
[XmlElement("AppointmentAvailabilityStatusResult")]
public AppointmentAvailabilityStatus appointmentAvailabilityStatus { get; set; }
}
[XmlRoot("AppointmentAvailabilityStatusResult", Namespace = "Appointments")]
public class AppointmentAvailabilityStatus
{
[XmlArray("DateAndTimeSlot", Namespace = "Appointments")]
[XmlArrayItem(typeof(DateAndTimeslot))]
public DateAndTimeSlots DateAndTimeSlot { get; set; }
[XmlElement("RequestedStatus")]
public int RequestedStatus { get; set; }
}
[XmlRoot(ElementName = "DateAndTimeSlot")]
[XmlType("a")]
public class DateAndTimeSlots : List<DateAndTimeslot> { }
[XmlRoot(ElementName = "DateAndTimeslot", Namespace = "Appointments.TO")]
[XmlType("b")] // if included this renames the node to "b" for some reason
public class DateAndTimeslot
{
[XmlElement("Date")]
public string Date { get; set; }
[XmlElement("TimeSlot")]
public string TimeSlot { get; set; }
}
缩短返回的XML,我想完全deserialise。
<AppointmentAvailabilityStatusResponse>
<AppointmentAvailabilityStatusResult xmlns:a="Appointments" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<a:DateAndTimeSlot xmlns:b="Appointments.TO">
<b:DateAndTimeslot>
<b:Date>14/07/2016</b:Date>
<b:TimeSlot>AM</b:TimeSlot>
</b:DateAndTimeslot>
<b:DateAndTimeslot>
<b:Date>14/07/2016</b:Date>
<b:TimeSlot>PM</b:TimeSlot>
</b:DateAndTimeslot>
</a:DateAndTimeSlot>
<a:RequestStatus>0</a:RequestStatus>
</AppointmentAvailabilityStatusResult>
</AppointmentAvailabilityStatusResponse>
XML如果我连载虚拟对象 - 其中一些我想要的差异整顿,不知道该命名空间是必要的deserialisation虽然
<AppointmentAvailabilityStatusResponse>
<AppointmentAvailabilityStatusResult>
<DateAndTimeSlot xmlns=\"Appointments\">
<DateAndTimeslot>
<Date xmlns=\"Appointments.TO\">today</Date>
<TimeSlot xmlns=\"Appointments.TO\">now</TimeSlot>
</DateAndTimeslot>
</DateAndTimeSlot>
<RequestedStatus xmlns=\"Appointments\">0</RequestedStatus>
</AppointmentAvailabilityStatusResult>
</AppointmentAvailabilityStatusResponse>
解串器
public static T DeserializeThis<T>(string cleanXml)
{
//string cleanXml = RemoveBom(dirtyXml);
bool check = cleanXml.TrimStart().StartsWith("<");
if (!string.IsNullOrEmpty(cleanXml) && cleanXml.TrimStart().StartsWith("<"))
{
try
{
XmlSerializer xs = new XmlSerializer(typeof(T));
MatchCollection mc = Regex.Matches(cleanXml, @"</?(\d\w+)");
List<string> elements = new List<string>();
foreach (Match m in mc)
{
string cpval = m.Groups[1].Value;
if (!elements.Contains(cpval)) { elements.Add(cpval); }
}
foreach (string e in elements)
{
cleanXml = cleanXml.Replace(e, "d_" + e);
}
using (MemoryStream ms = new MemoryStream(Encoding.UTF8.GetBytes(cleanXml)))
{
using (StringReader sr = new StringReader(cleanXml))
{
return (T)xs.Deserialize(sr);
}
}
}
catch(XmlException x)
{
var obj = (T)Activator.CreateInstance(typeof(T));
Type type = obj.GetType();
return (T)obj;
}
}
else
{
var obj = (T)Activator.CreateInstance(typeof(T));
Type type = obj.GetType();
// add in the generic derived class property search and assign
return (T)obj;
}
}
包含的代码,你实际上是试图将XML反序列化到所提供的对象图 - 我的第一个猜测是你错过了正确的'NamespaceManager' – Jamiec
可能是(包括我使用的derserialiser),但是,我不认为我需要在解串时使用命名空间?认为这只是在发送XML时没有收到序列化。 – PurpleSmurph
通过'http:// xmltocsharp.azurewebsites.net'解析你的'xml'来获得强类型的C#对象。 –