2017-02-09 19 views
0

我有2代表这是选择Aggregate ((数量*单价)/ 100)*折扣* 100)和AverageFreight =(运费/总项目按顺序)*总计行项目为了从多个表

我写的select语句是这样的:

select Orders.OrderID,CustomerID, EmployeeID, ProductID,ShippedDate, RequiredDate, ShipVia,(Freight/sum(Quantity))*Quantity 'TotalFreight', 
Quantity * UnitPrice 'LineItemTotal',sum(Quantity) 'Line Item Quantity',sum(((Quantity * UnitPrice)/100) * Discount*100) 'Total Line Discount',Discount from Orders 
inner join [Order Details] on Orders.OrderID = [Order Details].OrderID 
group by Orders.OrderID,Orders.CustomerID, Orders.EmployeeID, [Order Details].ProductID, Orders.RequiredDate, Orders.ShipVia, Orders.Freight, [Order Details].Quantity,[Order Details].UnitPrice, [Order Details].Discount, Orders.ShippedDate 

但是,它不计算AverageFreight权利。我究竟做错了什么? enter image description here

回答

2

您不需要为此进行聚合。窗口函数应该足够了:

select o.*, od.*, 
     (Freight/order_quantity)*Quantity as AllocatedFreight, 
     Quantity * UnitPrice as LineItemTotal, 
     Quantity as [Line Item Quantity], 
     (((Quantity * UnitPrice)/100) * Discount*100) as [Total Line Discount, 
     Discount 
from Orders o inner join 
    (select od.*, sum(quantity) over (partition by od.orderId) as order_quantity 
     from [Order Details] od 
    ) od 
    on o.OrderID = od.OrderID; 
+0

感谢您的快速回答。它工作得很好。但有没有办法做到这一点,而不使用'分区'? – Kranatos

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@Kranatos。 。 。我认为这是最简单的方法。 –

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是的。我只想练习更多关于聚合:) – Kranatos