2017-04-19 19 views
0

我需要合并两个数组以打印html 中的数据或直接打印数据,但使用我的代码打印重复的数据。合并两个数组以打印html中的数据

这是阵列来自数据库:

Array 
(
    [Course name] => English 4A 
    [Grade out of weight exam] => 47.25 
) 
Array 
(
    [Course name] => Humanities 4A 
    [Grade out of weight exam] => 45.00 
) 

Array 
(
    [FullName] => Adam Sherif Wahba Ibrahim Botros 
    [Course name] => English 4A 
    [Grade name] => 2nd Term 
    [Grade] => 74.25 
    [MAX] => 100.00 
    [Percentage] => 74.25 
    [Grade out of weight] => 247.50 
    [gi.aggregationcoef*100] => 333.33300 
) 


Array 
(
    [FullName] => Adam Sherif Wahba Ibrahim Botros 
    [Course name] => Humanities 4A 
    [Grade name] => 2nd Term 
    [Grade] => 73.20 
    [MAX] => 100.00 
    [Percentage] => 73.20 
    [Grade out of weight] => 244.00 
    [gi.aggregationcoef*100] => 333.33000 
) 

这是我的HTML代码和PHP

<table border='1'>   
    <tr class="tr">  
    <th class="th"> subject </th> 
    <th class="th"> student's Work out of </th> 
    <th class="th"> exam out of </th> 
    <th class="th"> total out of </th> 
    <th class="th"> Grade </th> 
    </tr> 
    <?php 
    $sql = "SELECT 
    c.fullname AS'Course name' , 
    ROUND(ROUND(gg.finalgrade/gg.rawgrademax * 100 ,2) *(gi.aggregationcoef*100)/100,2) AS 'Grade out of weight exam' 
    FROM 
    mdl_course AS c 
    JOIN mdl_grade_items AS gi ON gi.courseid = c.id 
    JOIN mdl_grade_grades AS gg ON gg.itemid = gi.id 
    JOIN mdl_user AS u ON u.id = gg.userid 
    WHERE gi.courseid = c.id AND gi.itemname in ('2nd Term EXAM') 
    AND gi.itemtype = 'Category' and u.id = '5'"; 

    $result = $conn->query($sql); 

     while($row = $result->fetch_assoc()) 
    { 
    extract($row); 

    echo '<pre>'; 
    print_r($row) ; 
    echo '</pre>'; 
    } 
    ///////////////// second SQL Get 2nd term 

    $sql2 = "SELECT 
    CONCAT(firstname, ' ', lastname) AS FullName , c.fullname AS'Course name' , gi.itemname AS 'Grade name', 
    ROUND(gg.finalgrade,2) AS Grade 
    ,ROUND(gg.rawgrademax,2) AS MAX, ROUND(gg.finalgrade/gg.rawgrademax * 100 ,2) AS Percentage 
    ,ROUND(ROUND(gg.finalgrade/gg.rawgrademax * 100 ,2) *(gi.aggregationcoef*100)/100,2) AS 'Grade out of weight' 
    ,gi.aggregationcoef*100 

    FROM 
    mdl_course AS c 
    JOIN mdl_grade_items AS gi ON gi.courseid = c.id 
    JOIN mdl_grade_grades AS gg ON gg.itemid = gi.id 
    JOIN mdl_user AS u ON u.id = gg.userid 
    WHERE gi.courseid = c.id AND gi.itemname in ('2nd Term') 
    AND gi.itemtype = 'Category' and u.id = '5'" 
    ; 

    $result2 = $conn->query($sql2); 
     while($row2 = $result2->fetch_assoc()) 
    { 
    extract($row2);  
    echo '<pre>'; 
    print_r($row2) ; 
    echo '</pre>'; 


    ?> 

    <tr class="tr"> 

    <td class="td"><?php echo $row2["Course name"]; ?></td> 
    <td class="td"><?php echo ($row2["Grade out of weight"] - $row["Grade out of weight exam"]); ?></td> 

    <td class="td"><?php echo $row["Grade out of weight exam"]; ?></td> 
    <td class="td"><?php echo $row2["Grade out of weight"]; ?></td> 
    <td class="td"><?php echo $row[""]; ?></td> 

    <?php 
    } 
    ?>  
    <td class="td"> </td>  
    </tr> 
</table> 
+0

玛吉=>合并,拖=>二,更正和更新您的问题请。 –

+0

请编辑你的问题,你的代码是不可读的。 –

回答

0
$array1 = []; 
foreach ($array2 as $key) { 
    $array1[] = $key; 
} 
foreach ($array3 as $key) { 
    $array1[] = $key; 
} 
var_dump($array1);