这里是一个小例子的数据帧:创建从数据帧与长度(列表)的列表相同nrow(DF)
> dput(head(cluster_socrata_csv))
structure(list(Cluster = structure(c(1L, 13L, 24L, 35L, 46L,
57L), .Label = c("cluster1", "cluster10", "cluster100", "cluster11",
"cluster12", "cluster13", "cluster14", "cluster15", "cluster16",
"cluster17", "cluster18", "cluster19", "cluster2", "cluster20",
"cluster21", "cluster22", "cluster23", "cluster24", "cluster25",
"cluster26", "cluster27", "cluster28", "cluster29", "cluster3",
"cluster30", "cluster31", "cluster32", "cluster33", "cluster34",
"cluster35", "cluster36", "cluster37", "cluster38", "cluster39",
"cluster4", "cluster40", "cluster41", "cluster42", "cluster43",
"cluster44", "cluster45", "cluster46", "cluster47", "cluster48",
"cluster49", "cluster5", "cluster50", "cluster51", "cluster52",
"cluster53", "cluster54", "cluster55", "cluster56", "cluster57",
"cluster58", "cluster59", "cluster6", "cluster60", "cluster61",
"cluster62", "cluster63", "cluster64", "cluster65", "cluster66",
"cluster67", "cluster68", "cluster69", "cluster7", "cluster70",
"cluster71", "cluster72", "cluster73", "cluster74", "cluster75",
"cluster76", "cluster77", "cluster78", "cluster79", "cluster8",
"cluster80", "cluster81", "cluster82", "cluster83", "cluster84",
"cluster85", "cluster86", "cluster87", "cluster88", "cluster89",
"cluster9", "cluster90", "cluster91", "cluster92", "cluster93",
"cluster94", "cluster95", "cluster96", "cluster97", "cluster98",
"cluster99"), class = "factor"), Socrata = structure(c(17L, 17L,
1L, 13L, 14L, 16L), .Label = c("Assault", "Assault with Deadly Weapon",
"Breaking and Entering", "Community Policing", "Death", "Disorder",
"Drugs ", "Missing Person", "Other", "Other Sexual Offense",
"Property Crime", "Property Crime Residental", "Robbery", "Theft",
"Theft from Vehicle", "Theft of Vehicle", "Traffic", "Unknown",
"Vehicle Recovery", "Weapons Offense"), class = "factor")), .Names = c("Cluster",
"Socrata"), row.names = c(NA, 6L), class = "data.frame")
看起来像这样:
> head(cluster_socrata_csv)
Cluster Socrata
1 cluster1 Traffic
2 cluster2 Traffic
3 cluster3 Assault
4 cluster4 Robbery
5 cluster5 Theft
6 cluster6 Theft of Vehicle
我想创建一个列表,其中集群是关键,Socrata是价值。
我试着简单地在一个as.list()函数中嵌套,但是这返回了一个包含2个值的列表,一个用于集群,另一个用于值。
在这种情况下,我想在这6个项目的列表,其中第一项关键是cluster1中,它的价值是交通。对于第六项来说,关键将是cluster6,它的价值是“盗窃车辆”。
谢谢,也可以,但它是返回所有级别,有没有办法来防止这种情况(请参阅zweps答案中的评论) –
我编辑了我的答案:) –