iOS 5在DatePicker中选择的日期

Question

我想在DatePicker中选择日期，但是我有一个滞后2小时的问题。

// String From Date 
NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; 
[dateFormatter setTimeStyle:NSDateFormatterFullStyle]; 
[dateFormatter setDateStyle:NSDateFormatterFullStyle]; 
[dateFormatter setLocale:[NSLocale currentLocale]]; 
[dateFormatter setDateFormat:@"yyyy-MM-dd HH:mm:ss ZZZ"]; 
NSDate *dateSelected = [datePicker date]; 
NSString *dateChoisie = [dateFormatter stringFromDate:dateSelected]; 
NSDate *dateFinal = [dateFormatter dateFromString:dateChoisie]; 

NSLog(@"dateSelected = %@", dateSelected); 
NSLog(@"dateChoisie = %@", dateChoisie); 
NSLog(@"dateFinal = %@", dateFinal); 

结果：

2011-10-15 00:16:11.129 QuickEvent[25459:707] dateSelected = 2011-10-14 22:20:05 +0000 
2011-10-15 00:16:11.132 QuickEvent[25459:707] dateChoisie = 2011-10-15 00:20:05 +0200 
2011-10-15 00:16:11.138 QuickEvent[25459:707] dateFinal = 2011-10-14 22:20:05 +0000 

Answer 1

尝试使用这种格式的..

NSTimeZone *sourceTimeZone =[NSTimeZone systemTimeZone]; 
NSTimeZone *destinationTimeZone = [NSTimeZone timeZoneForSecondsFromGMT:(TIME_ZONE_THAT_YOU_WANTED*3600)]; 

NSInteger sourceSeconds =[sourceTimeZone secondsFromGMTForDate:date]; 
NSInteger destinationSeconds =[destinationTimeZone secondsFromGMTForDate:date]; 
NSTimeInterval interval = destinationSeconds - sourceSeconds; 

NSDate *convertedDate =[[[NSDate alloc]initWithTimeInterval:interval sinceDate:date] autorelease]; 
return convertedDate; 

举一个例子，你可以申请TIME_ZONE_THAT_YOU_WANTED = -8纽约时区基于时间

谢谢， 阿伦。