2015-01-02 291 views
0

我被困在一个我相信应该工作的步骤中。我有一个方法(在一个单独的类中),它应该在处理JSON之后返回一个List作为它的值。我要粘贴代码跳过JSON配置的东西:将JSON转换为列表

public static dynamic CustInformation(string Identifier) 
    { 

    //SKIPPED JSON CONFIG STUFF (IT'S WORKING CORRECTLY) 

     var result = ""; 
     var httpResponse = (HttpWebResponse)httpWebRequest.GetResponse(); 
     dynamic d; 
     using (var streamReader = new StreamReader(httpResponse.GetResponseStream())) 
     { 
      result = streamReader.ReadToEnd(); 
     } 

     return JsonConvert.DeserializeObject<List<Models.RootObject>>(result); 
} 

是用C#为JSON转换器产生的模型:

public class Record 
{ 

    public string idIdentifier { get; set; } 
    public string KnowName1 { get; set; } 
    public string KnowAddress1 { get; set; } 
    public string KnowRelation1 { get; set; } 
    public string KnowPhone1 { get; set; } 
    public string KnowName2 { get; set; } 
    public string KnowAddress2 { get; set; } 
    //.....skipped other variables 

} 


public class RootObject 
{ 
    public List<Record> record { get; set; } 
} 

我打电话来是这样的方法:

var model = Classes.EndPoint.CustInformation(identifier); 

但我得到这个错误每次:

Cannot deserialize the current JSON object (e.g. {"name":"value"}) into type  'System.Collections.Generic.List`1[Models.RootObject]' because the type requires a JSON array (e.g. [1,2,3]) to deserialize correctly. 
    To fix this error either change the JSON to a JSON array (e.g. [1,2,3]) or change 
the deserialized type so that it is a normal .NET type (e.g. not a primitive type like integer, not a collection type like an array or List<T>) that can be deserialized from a JSON object. JsonObjectAttribute can also be added to the type to force it to deserialize from a JSON object. 
Path 'record', line 1, position 10. 

编辑:JSON

{ 
    "record": [ 
    { 
     Identifier": "DQRJO1Q0IQRS", 
     "KnowName1": "", 
     "KnowAddress1": "", 
     "KnowRelation1": "", 
     "KnowPhone1": "", 
     "KnowName2": "", 
     "KnowAddress2": "", 
     //.....MORE STYFF 
    } 
    ] 
} 
+2

错误很明显:它期待一个json数组,并且你没有提供这个。你打给电话的json是什么? –

+1

您正在序列化一个包含Record对象列表的根对象。但是,您正在反序列化包含记录对象列表的根对象列表。你需要确保你序列化和反序列化到相同的类型。 – mason

+0

发表了JSON Marc,它应该“排队” –

回答

4

就像我在评论中说,和喜欢的错误信息中明确指出,你想反序列化为根对象的列表,但你的JSON只有一个根对象,不数组。

这是你的C#应该是什么。

return JsonConvert.DeserializeObject<Models.RootObject>(result); 
+0

OOOOH !!!!现在我懂了!非常感谢梅森,感谢梅森。它就在我的面前> _ <! –