2013-04-22 62 views
1

我有这个网址,我试图通过bit.ly API缩短网址。这里是我的代码缩短包含&参数的网址

NSString *url = @"http://www.example.com&username=abc&password=123&mode=offline"; 

NSString *requestStr = [NSString stringWithFormat:@"http://api.bit.ly/v3/shorten?login=%@&apiKey=%@&longUrl=%@&format=txt",login, api_key, url]; 

    requestStr = [requestStr stringByReplacingOccurrencesOfString:@"&" withString:@"&"]; 

    NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:requestStr]]; 
    NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; 
    NSString *response = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding]; 

我得到响应的URL对应唯一http://www.example.com

出人意料的是,&用户名= ABC &密码= 123 &模式= URL的离线部分进行修剪。 只有当我通过xcode进行时才会发生这种情况。在网站上,它工作正常。请帮忙。

回答

1
NSString *url = @"https://www.googleapis.com/urlshortener/v1/url?key=UR_KEY"; 

    NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:[NSURL URLWithString:url]]; 
    [request setValue:@"application/json" forHTTPHeaderField:@"Content-Type"]; 
    [request setHTTPMethod:@"POST"]; 

    NSDictionary *dict = [NSDictionary dictionaryWithObjectsAndKeys:@"UR_LONG_URL",@"longUrl", nil]; 

    [request setHTTPBody:[[dict JSONRepresentation] dataUsingEncoding:NSUTF8StringEncoding]]; 

    NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:nil error:nil]; 
    NSString *response = [[NSString alloc] initWithData:returnData encoding:NSUTF8StringEncoding];