如何在捕获异常后继续执行？

Question

我使用twython从twitter获取一些推文。为了得到推文我使用尝试/除了，就像

for follower in followers_file_id: 
    follower = follower.strip() 
    try:  
     if req_user_settings > max_user_settings_req or req_user_tweets > max_tweets_req: 
     time.sleep(15 * 60) 
     tweets_file_name = tweetsFileName(followed_user) 

     user_settings = twitter.show_user(user_id = follower) 
     req_user_settings += 1 

     if not user_settings['protected'] and user_settings['statuses_count'] > 0: 
     tweets = twitter.get_user_timeline(user_id = follower, count = 200, page = 1) 
     req_user_tweets += 1 

     n_tweets =tweets[0]['user']['statuses_count'] 
     n_loops = n_tweets // max_tweets_per_page + 1 
     if n_loops > max_tweet_pages: 
     n_loops = max_tweet_pages 

     if tweets[0]['user']['lang'] == 'en': 
     n_crawled_tweets = writeTweets(tweets, tweets_file_name, n_crawled_tweets) 

     for i_loop in range(1, n_loops):   
     tweets = twitter.get_user_timeline(user_id = follower, count = 200, page = i_loop+1) 
     n_crawled_tweets = writeTweets(tweets, tweets_file_name, n_crawled_tweets) 
     req_user_tweets += 1 

    except TwythonError as e: 
     print str(e) 

如何告诉程序打印错误后继续执行？原因现在在打印错误后，程序停止。

Answer 1

整个try块将尽快发生异常离开。 如果您想异常后继续进行，你需要捕获异常早期

像

Try: 
    some code here 
except TwythonError as e: 
    print e 

some more code here 

Answer 2

try: 
    some code here 
except TwythonError as e: 
    print e 
finally: 
    #continue 

记住，代码总是要经过最后部分，因此，你只能执行引发异常的代码，在try部分中，其余部分在finally部分中执行。