ObjectGetOptions options = new ObjectGetOptions();
ManagementPath p = new ManagementPath("\\\\server01\\root" + "\\cimv2:Win32_Share");
// Make a connection to a remote computer.
ManagementScope scope = new ManagementScope("\\\\server01\\root\\cimv2");
scope.Connect();
// Create a ManagementClass object
ManagementClass managementClass = new ManagementClass(scope, p, options);
// Create ManagementBaseObjects for in and out parameters
ManagementBaseObject inParams = managementClass.GetMethodParameters("Create");
ManagementBaseObject outParams;
// Set the input parameters
//inParams["Description"] = String.Empty;
inParams["Name"] = "test";
inParams["Path"] = @folderPath;
inParams["Type"] = 0x0; // Disk Drive
// Invoke the method on the ManagementClass object
outParams = managementClass.InvokeMethod("Create", inParams, null);
// Check to see if the method invocation was successful
if ((uint)(outParams.Properties["ReturnValue"].Value) != 0)
{
throw new Exception("Unable to share directory. Error code: " + outParams.Properties["ReturnValue"].Value);
}
}
catch (Exception e)
{
MessageBox.Show(e.Message.ToString());
}
}
我正在使用以下代码来设置共享,但我总是得到9的返回值,这意味着无效的名称。我传递一个字符串,并试图使用明确的字符串,我仍然得到错误9.以编程方式创建共享失败,错误9
我创建远程共享,而不是在本地计算机上。我试图确保连接到远程WMI提供程序,但我不确定自己是否成功。
WMI大师和其他人的任何建议是非常感谢。
感谢共享 – MichaelS 2014-02-26 15:10:44
除非路径为驱动器的根,例如 -
25未知设备或目录C:\。然后反斜杠是必需的。 – 2015-08-24 18:21:03