如何使用JSONModel

得到一个NSArray的对象，我有一个问题，在阅读JSON通过JSONModel库https://github.com/icanzilb/JSONModel 如何使用JSONModel

，并使用KivaDemo在JSonModel应用程序，该JSON：

我想要得到的“恩”，

@interface KivaFeed : JSONModel 

@property (strong, nonatomic) NSArray<LoanModel, ConvertOnDemand>* loans; 

@property (strong, nonatomic) Paging *paging; 

@end 


@protocol LoanModel @end  

@interface LoanModel : JSONModel 

@property (strong, nonatomic) NSString* name; 
@property (strong, nonatomic) NSString* status; 
@property (strong, nonatomic) NSString* use; 


@property (strong, nonatomic) NSString* id; 
@property (strong, nonatomic) NSString* funded_amount; 




@property (strong, nonatomic) LocationModel* location; 

@property (strong, nonatomic) Image* image; 

@property (strong, nonatomic) Description* description; 

@end

@interface说明：JSONModel

@property (strong, nonatomic) NSArray<Languages, ConvertOnDemand>* languages; 

@end 


@protocol Languages @end  

@interface Languages : JSONModel 

@end 

kiva = [[KivaFeed alloc] initFromURLWithString:@"http://api.kivaws.org/v1/loans/search.json?status=fundraising" 
     completion:^(JSONModel *model, JSONModelError *e) { 

      [table reloadData]; 

      NSLog(@"kiva.paging.page:%@",kiva.paging.page); 

      if (e) { 
       [[NSAlert alertWithError:e] beginSheetModalForWindow:self.view.window modalDelegate:nil didEndSelector:nil contextInfo:nil]; 
      } 

      [self setLoaderVisible:NO]; 
     }]; 



    LoanModel* loan = kiva.loans[row]; 
      NSString* message = [NSString stringWithFormat:@"%@ from %@(%@) needs a loan %@", 
           loan.name, loan.location.country, loan.location.countryCode, loan.use 
           ]; 

      NSLog(@"loan:%@",loan.id); 
      NSLog(@"loan:%@",loan.funded_amount); 
      NSLog(@"loan.image.id:%@",loan.image.id); 



      NSLog(@"loan.description.languages:%@",loan.description.languages[0]);

最后给我2013-04-15 13：16：09.163 JSONModelDemo_OSX [2308：303] loan.description.languages：（null）。如何获得en，我的代码有什么错误？

来源

2013-04-15 pengwang

做其他的 “'NSLog'” 线条为你工作？ –

是的，其他是正确的。 – pengwang

修改为：

@interface Description : JSONModel 
    @property (strong, nonatomic) NSArray* languages; 
    @end

一切正常

来源

2013-04-15 05:57:40 pengwang

如何使用JSONModel

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