这是一个相当长的问题,我可能会错过某些内容,所以如果需要更多信息,请提问。使用google-docs-api排序错误
我一直在使用scaperwiki从谷歌学者那里搜索数据,直到最近我只是把所有的网址都放在这里。
elec_urls = """http://1.hidemyass.com/ip-5/encoded/Oi8vc2Nob2xhci5nb29nbGUuY29tL2NpdGF0aW9ucz91c2VyPWo0YnRpeXNBQUFBSiZobD1lbg%3D%3D&f=norefer
http://4.hidemyass.com/ip-1/encoded/Oi8vc2Nob2xhci5nb29nbGUuY29tL2NpdGF0aW9ucz91c2VyPVZXaFJiZEFBQUFBSiZobD1lbg%3D%3D&f=norefer
http://4.hidemyass.com/ip-2/encoded/Oi8vc2Nob2xhci5nb29nbGUuY29tL2NpdGF0aW9ucz91c2VyPV84X09JSWNBQUFBSiZobD1lbg%3D%3D&f=norefer
http://1.hidemyass.com/ip-4/encoded/Oi8vc2Nob2xhci5nb29nbGUuY29tL2NpdGF0aW9ucz91c2VyPUh3WHdmTGtBQUFBSiZobD1lbg%3D%3D&f=norefer
http://4.hidemyass.com/ip-1/encoded/Oi8vc2Nob2xhci5nb29nbGUuY29tL2NpdGF0aW9ucz91c2VyPXU1NWFWZEFBQUFBSiZobD1lbg%3D%3D&f=norefer
""".strip()
elec_urls = elec_urls.splitlines()
我再花葶每一页,并把我想类型的字典列表中的信息,排序一次,删除重复项,然后再使用不同的密钥进行排序的话,我再导出我想要的信息到谷歌文档电子表格。这工作100%。
我试图改变它,以便我可以有另一个Google文档电子表格,并且从这里我可以放入所有的URL并且它会执行相同的操作。以下是我迄今为止所做的。
def InputUrls(Entered_doc, EnteredURL):
username = 'myemail'
password = 'mypassword'
doc_name = Entered_doc
spreadsheet_id = Entered_doc
worksheet_id = 'od6'
# Connect to Google
gd_client = gdata.spreadsheet.service.SpreadsheetsService()
gd_client.email = username
gd_client.password = password
gd_client.source = EnteredURL
gd_client.ProgrammaticLogin()
#Now that we're connected, we query the spreadsheet by name, and extract the unique spreadsheet and worksheet IDs.
rows = gd_client.GetListFeed(spreadsheet_id, worksheet_id).entry
#At this point, you have a row iterator which will yield rows for the spreadsheet. This example will print everything out, keyed by column names:
urlslist = []
for row in rows:
for key in row.custom:
urlslist.append(row.custom[key].text)
return urlslist
def URLStoScrape(ToScrape):
Dep = []
for i in range(0,len(ToScrape)):
Department_urls = ToScrape[i].strip()
Department_urls = Department_urls.splitlines()
Done = MainScraper(Department_urls)
Dep.append(Done)
return Dep
ElectricalDoc = '0AkGb10ekJtfQdG9EOHN0VzRDdVhWaG1kNVEtdVpyRlE'
ElectricalUrl = 'https://docs.google.com/spreadsheet/ccc? '
ToScrape_Elec = InputUrls(ElectricalDoc, ElectricalUrl)
这似乎很好,但然后当程序去排序我得到下面的错误。
回溯(最近通话最后一个): 文件 “./code/scraper”,线路230,在 Total_and_Hindex_Electrical = GetTotalCitations(电气) 文件 “./code/scraper”,行89,在GetTotalCitations Wrt_CitationURL = Sorting(Department,“CitationURL”) 文件“./code/scraper”,第15行,排序 SortedData = sorted(Unsorted,reverse = True,key = lambda k:k [pivot]) 文件“代码/刮板“,第15行,在 SortedData = sorted(Unsorted,reverse = True,key = lambda k:k [pivot]) TypeError:列表索引必须是整数,而不是str
我认为,几乎可以肯定的是,它与URLStoScrape函数有关,但我不知道如何解决它,任何帮助都会很棒。
谢谢你让我知道,如果需要
它看起来像枢轴变量是一个字符串,而不是一个整数。你可以发布sorted()的代码吗? – raphonic
以下是排序功能的代码。 def Sorting(Unsorted,pivot): SortedData = sorted(Unsorted,reverse = True,key = lambdak:k [pivot]) return SortedData – Totothejuggler