RestKit可以连接关系而不将外键存储为属性,即直接来自JSON中的键路径?RestKit对象与外键的映射关系
特别是,我有一个工作has_many房关系。房间的JSON不包含作业,而是两者分别加载:
- job: {
id: 1,
name: "John"
}
- room: {
id: 4,
job_id: 1,
name: "spare bedroom"
}
作业在房间之前加载。
我CoreData模型,工作有
@interface Job : NSManagedObject
@property (nonatomic, retain) NSNumber * identifier;
@property (nonatomic, retain) NSString * name;
@property (nonatomic, retain) NSSet *rooms;
@end
@interface Room : NSManagedObject
@property (nonatomic, retain) NSNumber * identifier;
@property (nonatomic, retain) NSString * name;
@property (nonatomic, retain) Job *job;
@end
性质目前我添加了一个@property (nonatomic, strong) NSNumber *jobID;
到房间,我@synthesize
。
JobMapping:
mapping = [RKManagedObjectMapping mappingForClass:[Job class]];
[mapping setPrimaryKeyAttribute:@"identifier"];
[mapping mapAttributes:@"name", nil];
[mapping mapKeyPath:@"id" toAttribute:@"identifier"];
[mapping mapRelationship:@"rooms" withMapping:[Room objectMapping]];
RoomMapping
mapping = [RKManagedObjectMapping mappingForClass:[Room class]];
[mapping setPrimaryKeyAttribute:@"identifier"];
[mapping mapAttributes:@"name", nil];
[mapping mapKeyPath:@"id" toAttribute:@"identifier"];
[mapping mapKeyPath:@"job_id" toAttribute:@"jobID"];
[mapping mapRelationship:@"job" withMapping:[Job objectMapping]];
[mapping connectRelationship:@"job" withObjectForPrimaryKeyAttribute:@"jobID"];
我在想,如果有一种方法,我可以做到这一点没有额外的作业ID属性?我不想在CoreData xcdatamodeld中有一个jobID属性 - 它是多余的,因为关系覆盖了这个属性。
此外,如果我重建NSManagedObjects,我需要重新添加jobID属性,这是乏味的。我不能通过JSON中的job_id keypath来告诉restkit将Room连接到相应的Job吗?
如果我删除的特性,mapKeyPath:@"job_id"
线,并更改最后一行[mapping connectRelationship:@"job" withObjectForPrimaryKeyAttribute:@"job_id"];
我得到
the entity Room is not key value coding-compliant for the key "job_id".
您是否已经发现如何正确连接核心数据中的关系,而没有在真实关系旁边具有冗余ID属性? – thejaz 2013-05-24 14:24:32