循环问题 - UIMA鲁塔

Question

目的：

要分配的标题级别。

第一个标题是分配的级别1.我提取字体系列和它的大小，寻找匹配的标题。一旦级别被分配，我取消标题的标题，在另一个注释（HeadingHierarchy）中保留标题&。等级完成后，只要Headinglevel注释中剩下任何标题，就会一次又一次调用同一个块。

问题：

该脚本工作正常，发现所有1级标题。但是，当通过Call语句执行该块时，它仅找到每个级别的第一个匹配（级别2以上）。因此电平为低于输入的总数变为10，而它必须是4。

输入：（.txt）的

Apache UIMA Ruta Overview =>Arial,18 
What is Apache UIMA Ruta? =>Arial,16 
Getting started =>Arial,16 
UIMA Analysis Engines =>Arial,16 
Ruta Engine =>Times New Roman,14 
Configuration Parameters =>Arial,10 
Annotation Writer =>Times New Roman,14 
Configuration Parameters =>Arial,10 
Apache UIMA Ruta Language =>Arial,18 
Syntax =>Arial,16 
Rule elements and their matching order =>Arial,16 

脚本：

PACKAGE uima.ruta.example; 

DECLARE Headinglevel(STRING family, INT size, INT level); 
DECLARE HeadingHierarchy(STRING family, INT size, INT level); 
DECLARE FontFamily, FontSize; 

STRING family; 
INT size; 

RETAINTYPE(BREAK); 
    BREAK? #{-PARTOF(Headinglevel)} @SPECIAL+ W+ COMMA NUM{->MARK(Headinglevel,2,6), MARK(HeadingHierarchy,2,6), MARK(FontFamily,4), MARK(FontSize,6)}; 
RETAINTYPE; 

h:Headinglevel{->h.family = family, HeadingHierarchy.family = family} 
<-{FontFamily{PARSE(family)};}; 

h:Headinglevel{->h.size = size, HeadingHierarchy.size = size} 
<-{FontSize{PARSE(size)};}; 

INT i=1; 

BLOCK(ForEachHeadLevel)Document{} 
{ 
    # h:Headinglevel{-> family = h.family, size = h.size}; 
    h:Headinglevel{AND(h.family == family, h.size == size)-> h.level=i, HeadingHierarchy.level = i, UNMARK(h)}; 
} 
Headinglevel{->i=i+1, CALL(Test2.ForEachHeadLevel)}; 
Document{->LOG(" LEVELS : " + (i))}; 

预计产量：

HeadingHierarchy      Feature 

Apache UIMA... =>Arial,18     level: 1 
What is Apa... =>Arial,16     level: 2 
Getting sta... =>Arial,16     level: 2 
UIMA Analys... =>Arial,16     level: 2 
Ruta Engine... =>Times New Roman,14  level: 3 
Configurati... =>Arial,10     level: 4 
Annotation ... =>Times New Roman,14  level: 3 
Configurati... =>Arial,10     level: 4 
Apache UIMA... =>Arial,18     level: 1 
Syntax =>Ar... =>Arial,16     level: 2 
Rule elemen... =>Arial,16     level: 2 

Answer 1

问题是CALL限制了规则元素匹配的跨度上的窗口。这意味着BLOCK仅在现有的Headinglevel注释中执行。但是，您需要拥有完整的文档，以便块中的第二条规则完成其工作。

这是最有可能不是最好的解决办法，但来到了我的脑海里的第一个。

你可以在块内无论CALL行动的限制与DOCUMENTBLOCK重置窗口完整的文档：

BLOCK (ForEachHeadLevel)Document{} 
{ 
    DOCUMENTBLOCK Document{} 
    { 
     # h:Headinglevel{-> family = h.family, size = h.size}; 
     h:Headinglevel{AND(h.family == family, h.size == size)-> h.level=i, HeadingHierarchy.level = i, UNMARK(h)}; 
    } 
} 

DOCUMENTBLOCK是块扩展。您需要在additionalExtensions配置参数中包含org.apache.uima.ruta.block.DocumentBlockExtension。

下面是使用foreach块的其他的解决方案：

INT i=0; 
FOREACH(hl) Headinglevel{}{ 
    hl{IS(Headinglevel)-> i=i+1, family = hl.family, size = hl.size}; 
    h:Headinglevel{h.family == family, h.size == size -> h.level=i, HeadingHierarchy.level = i, UNMARK(h)}; 
} 

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