Zend的SQL语句来查找和occurances

Question

为了结果我有一个看起来像这样的表：

 
ID | name | phone_number | date 
1 | bob | 4567   | 1/1/2011 
2 | bob | 8912   | 1/1/2010 
3 | bob | 1234   | 1/1/2010 
4 | bob | 1234   | 1/1/2014 
5 | bow | 4567   | 1/1/2014 

我创建一个自动提示，以便用户键入的名字就会拿起以前的名字和电话数字。由于人们可以更改他们的电话号码，我想要订购结果并根据最常用的电话号码显示号码的数量。作为第二种，它应该基于名称和添加日期的最后一种（最新的第一种）。

因此，如果有人类型的“博”，它应该返回：

 
bob 1234 (2) - Because it is alphabetically highest plus has the most phone numbers. 
bob 4567 (1) - Because it is alphabetically highest and its last entry is newer. 
bob 8912 (1) - Because it is alphabetically highest and its last entry was older. 
bow 4567 (1) - Because it is alphabetically lower. 

通常我会用例如Zend的方法：

public function getAllNames($part) 
{ 
    $select = $this->select(); 
    $select->where('name LIKE ?', '%'.$part.'%') 
      ->order('name'); 
    return $this->fetchAll($select)->toArray(); 
} 

但我被困在如何计算的项电话号码，然后执行三个命令。

或者只是获取所有条目并使用PHP来处理结果并相应地排序它会更好吗？

Answer 1

以下情况如何？

public function getAllNames($part) 
{ 
    $select = $this->select(); 
    $select->where('name LIKE ?', '%'.$part.'%') 
      ->order('name') 
      ->order(new \Zend\Db\Sql\Expression('LENGTH(phone_number)')) 
      ->order('date desc'); 
    return $this->fetchAll($select)->toArray(); 
} 

修订ANSWER

public function getAllNames($part) 
{ 
    $select = $this->select(); 
    $select->where('name LIKE ?', '%'.$part.'%') 
      ->group('name') 
      ->group('phone_number') 
      ->order('name') 
      ->order(new \Zend\Db\Sql\Expression('count(phone_number) DESC')) 
      ->order(new \Zend\Db\Sql\Expression('max(date) DESC')); 
    return $this->fetchAll($select)->toArray(); 
} 

另一个更新：使用MAX（日期）是没有必要的

public function getAllNames($part) 
{ 
    $select = $this->select(); 
    $select->where('name LIKE ?', '%'.$part.'%') 
      ->group('name') 
      ->group('phone_number') 
      ->order('name') 
      ->order(new \Zend\Db\Sql\Expression('count(phone_number) DESC')) 
      ->order('date DESC'); 
    return $this->fetchAll($select)->toArray(); 
} 

Answer 2

如果我理解正确的话......

DROP TABLE IF EXISTS my_table; 

CREATE TABLE my_table 
(ID INT NOT NULL AUTO_INCREMENT PRIMARY KEY 
,name VARCHAR(12) NOT NULL 
,phone_number VARCHAR(12) NOT NULL 
,date DATE NOT NULL 
); 

INSERT INTO my_table VALUES 
(1 ,'bob','4567','2011-01-01'), 
(2 ,'bob','8912','2010-01-01'), 
(3 ,'bob','1234','2010-01-01'), 
(4 ,'bob','1234','2014-01-01'), 
(5 ,'bow','4567','2014-01-01'); 


SELECT x.* 
     , y.total 
    FROM my_table x 
    JOIN 
     (SELECT name 
      , phone_number 
      , MAX(date) n_date 
      , COUNT(*) total 
      FROM my_table 
     WHERE name LIKE 'bo%' 
     GROUP 
      BY name 
      , phone_number 
    ) y 
    ON y.name = x.name 
    AND y.phone_number = x.phone_number 
    AND y.n_date = x.date 
    ORDER 
    BY x.name 
     , y.total DESC 
     , x.date DESC; 
+----+------+--------------+------------+-------+ 
| ID | name | phone_number | date  | total | 
+----+------+--------------+------------+-------+ 
| 4 | bob | 1234   | 2014-01-01 |  2 | 
| 1 | bob | 4567   | 2011-01-01 |  1 | 
| 2 | bob | 8912   | 2010-01-01 |  1 | 
| 5 | bow | 4567   | 2014-01-01 |  1 | 
+----+------+--------------+------------+-------+ 

Answer 3

这是我实际使用的答案，感谢user3511578。正如在评论中，我没有在我的Zend库表达模块，所以我做了这样的：

万一它有助于任何人在未来：

public function getAllNames($part) 
{ 
    $select = $this->select(); 
    $select->from($this->_name, array('name', 'phone_number', 'count'=>'COUNT(phone_number)')) 
      ->where('name LIKE ?', '%'.$part.'%') 
      ->group('name') 
      ->group('number') 
      ->order('name') 
      ->order('count DESC') 
      ->order('date desc'); 
    return $this->fetchAll($select)->toArray(); 
}