-2
嗨我有问题,因为此功能创建我想要的数字,但也产生None
。我应该怎么写这段代码不会产生NONE如何让这个功能不消失?
def binary (str):
b = []
for x in str:
b.append(format(ord(x), 'b'))
return ((b))
clave = "1001001000010001001000110111111100110000100011001010100000110001110110011111010010011111000011111001000011101011001101000001110010011110010110000000"
c = list(clave)
msg = binary("Lol")
print("".join(msg))
m = list("".join(msg))
print("Now the right")
def OTP(m,c):
for i in range (0,len(m)):
if c[i]== "1" and m[i]== "1":
m.pop(i)
m.insert(i,"0")
elif c[i] == "1" and m[i] == "0":
m.pop(i)
m.insert(i,"1")
return print("".join(m))
msg1 = OTP(m,c)
print(msg1)
这不可能是你的代码:一旦我固定的缩进你,你可以从你有一条线一个无与伦比的报价高亮看到。请复制并粘贴您的实际代码。 – Duncan
出于好奇 - 你和拉斐尔在同一课程? http://stackoverflow.com/questions/19497000/list-index-out-of-range-error –