mysql select不工作IN IN

Question

BEGIN 
DECLARE cnt1 int(11); 
DECLARE cnt2 int(11); 
DECLARE demandid varchar(255); 
set demandid = replace(pintypeid,';',','); 

SELECT 
    COUNT(*) into cnt1 
FROM 
    UK_Generic_Demand_Details 
where status =300 and 
policyNumber =pinpno and 
demandTypeId in(Select @demandid) ; 

    SELECT 
    COUNT(*) into cnt2 
FROM 
    UK_Generic_Completed_Demand_Details 
    where 
     status =300 and 
policyNo =pinpno and 
demandTypeId in(select @demandid); 
     select cnt1+cnt2 into poutcount; 

END 

可以请一些建议我解决这个问题。 存储过程将从应用程序调用pintypeid和policynumber作为输入。 policynumber将单个，但pintypeid将像一个字符串。

Answer 1

您可能正在寻找find_in_set

BEGIN 
DECLARE cnt1 int(11); 
DECLARE cnt2 int(11); 
DECLARE demandid varchar(255); 
set demandid = replace(pintypeid,';',','); 

SELECT 
    COUNT(*) into cnt1 
FROM 
    UK_Generic_Demand_Details 
where status =300 and 
policyNumber =pinpno and 
find_in_set(demandTypeId, @demandid) > 0; 

    SELECT 
    COUNT(*) into cnt2 
FROM 
    UK_Generic_Completed_Demand_Details 
    where 
     status =300 and 
policyNo =pinpno and 
find_in_set(demandTypeId, @demandid) > 0; 
     select cnt1+cnt2 into poutcount; 

END