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尝试创建对象的新实例。我想制作一部新电影,并将其显示在数组列表中。“无法解析为类型”
所以我有两个类。
1类
public class Films {
//Film Attributes
private String title, studio, director;
private int release, duration, rating;
//default constructor
public Films(){
title = null;
studio = null;
director = null;
release = 0;
duration = 0;
rating = 0;
}
//Start of Film method
public void setFilms(String title, String studio, String director,
int release, int duration, int rating)
{
this.title = title;
this.studio = studio;
this.director = director;
this.release = release;
this. duration = duration;
this.rating = rating;
}//end of Film method
//Start of getString method
public String getString(){
return "\nTitle: " + title + "\nRelease: " + release + "\nDuration: " + duration
+ "\nStudio: " + studio + "\nDirector: " + director + "\nRating: " + rating
+ "\n";
}//end of getString method
}
和类2
//start of createFilm() method
private static void createFilm(){
Films newfilm = new Films(); //create a new instance of a film object
System.out.println("Film Title: ");
String title = in.next();
System.out.println("Release Date: ");
int release = in.nextInt();
System.out.println("Duration: ");
int duration = in.nextInt();
System.out.println("Studio: ");
String studio = in.next();
System.out.println("Director: ");
String director = in.next();
System.out.println("Rating: ");
int rating = in.nextInt();
newfilm.setFilms(title, release, duration, studio, director, rating);
myfilms.add(newfilm);
}
}
我只包括其中我在2类具有麻烦基本上该方法麻烦我在第二课,是线路;
Films newfilm = new Films(); //create a new instance of a film object
告诉我'电影无法解析为类型'x2。所以这两个'电影'。
我想象它的东西非常愚蠢和愚蠢,我忽略了,假设或错过了,但我无法弄清楚问题是什么。
这是我在这个问题上的第一篇文章,因为如果我错过了有价值的关键信息和代码的一部分,你可能会告诉我这么抱歉。我是编程新手。
你在2类进口'Films'? – Berger
听起来像是一个导入问题,也是一个旁注,在您的Films类的构造函数中,没有必要将这些变量设置为null,它们在那时已经是null了。 – px06
@Berger,如果它在同一个包中,则不需要导入。 – RealSkeptic