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我正在被加载的jQuery脚本,但是当我通过我正在此错误的PHP加载:当我看到未捕获的类型错误:对象[对象的对象]无方法“facebookTrafficPop”
Uncaught TypeError: Object [object Object] has no method 'facebookTrafficPop'
通过Chrome浏览器开发consule,我可以看到它complaines哪些这一行:
jQuery().facebookTrafficPop({
这是我在我的PHP代码:
<script type="text/javascript">
jQuery(document).ready(function(){
jQuery().facebookTrafficPop({
title: '<?php echo $params->get('title', 'Facebook Like Us Popup'); ?>',
message: '<?php echo $params->get('message', ''); ?>',
url: '<?php echo $params->get('url', $url); ?>',
showfaces: <?php echo $params->get('showfaces', '1'); ?>,
timeout: '<?php echo $params->get('timeout', '60'); ?>',
delay: '<?php echo $params->get('delay', '0'); ?>',
closeable: <?php echo $params->get('closeable', '1'); ?>,
advancedClose: <?php echo $params->get('advancedClose', '1'); ?>,
wait: '<?php echo $params->get('wait', '0'); ?>',
//lang: '<?php echo $params->get('lang', 'en'); ?>',
lang: '<?php echo $lang->getTag(); ?>',
opacity: '<?php echo $params->get('opacity', '25'); ?>'
});
});
</script>
,这就是我在Chrome中看到:
<script type="text/javascript">
//<script type="text/javascript" language="javascript">
// jQuery.noConflict();
jQuery(document).ready(function(){
jQuery().facebookTrafficPop({
**Uncaught TypeError: Object [object Object] has no method 'facebookTrafficPop'**
title: 'Facebook Like Us Popup',
message: '',
url: 'https://www.facebook.com/Arab.Dentist.Network',
showfaces: 1,
timeout: '60',
delay: '0',
closeable: 0,
advancedClose: 0,
wait: '0',
//lang: 'en',
lang: 'en-GB',
opacity: '25'
});
});
</script>
请让我知道,如果你能解决这个问题有所帮助。
,如果我做什么@Trew建议,我得到这个错误:Uncaught TypeError:Object function(a,b){return new e.fn.init(a,b,h)}没有方法'facebookTrafficPop' – 2012-08-05 07:44:00
你有一些我们可以测试的网站,或者链接到哪里获取插件? – ThoKra 2012-08-05 07:45:04
当然,@Trew我现在在这里加载它https://innovations-it.com/zoo_demo/en/social-web/facebook-like-us-popup-module – 2012-08-05 07:50:48