我知道最终我需要将trigram,其中一个空格包含来自前一个字符串的3个字符,更改为一个动态数组来解决这个问题,但我试图首先设置我的阵列容量足够大。但是,当我编译我的代码时,会显示错误。错误:非POD元素类型“字符串”(又名'basic_string <char>')的可变长度数组
#error: variable length array of non-POD element type 'string' (aka 'basic_string<char>'#
代码:
//global variable
int CAPACITY = 1000;
int main()
{
//a string that reads in the language of the text
string language = "";
//a string that reads in the file name of the text
string filename = "text.txt";
//a string that reads in the original text characters
string original = "";
//a string that reads in the modified original array
string rid_of_spaces = "";
//an array with capacity that stores the trigrams
string trigrams[CAPACITY];
ifstream finput;
char c;
//the length of an array
int sLength = 0;
//the tracker for trigrams
int counter = 0;
cin >> language >> filename;
finput.open(filename.c_str());
while (finput.get(c)){
//to test if the character is alpha
if (isalpha(c)){
//change the alphabet to lowercase
c = tolower(c);
//store the modified letter in the array
original += c;
}
//change any other characters into a space
else original += ' ';
}
sLength = original.length();
//loop through the original array and change mutiple spaces into one
for (int i = 0; i < sLength; i++){
if (isalpha(original[i]))
rid_of_spaces += original[i];
else {
while (original[i] == ' ')
i++;
rid_of_spaces += ' ';
rid_of_spaces += original[i];
}
}
sLength = rid_of_spaces.length();
for (int i = 0; i < CAPACITY; i++)
trigrams[i] = 0;//initialize each element to 0
for (int i = 0; i < sLength - 2; i++){
trigrams[counter] += rid_of_spaces[i]
+ rid_of_spaces[i + 1]
+ rid_of_spaces[i + 2];
counter++;
}
cout << filename << endl;
cout << original << endl;
cout << rid_of_spaces << endl;
for (int i = 0; i < counter; i++)
cout << trigrams[i] << endl;
finput.close();
return 0;
}
如何使用'std :: vector'而不是动态数组? – MikeCAT
尝试'const int CAPACITY' – user463035818
@MikeCAT对不起,但不知道是什么 –