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我在脚本中使用以下行。gnuplot输入的bash脚本
foo=$1
bar=$(printf ' , "%s" u ($1):($2) lw 8 ti' ${foo[@]} ${foo[@]} ${foo[@]} ${foo[@]} )
bar=${bar:2}
echo $bar
这将产生以下行变量酒吧
"rdf_inter_fortran_05-25.xvg" u ($1):($2) lw 8 ti , "rdf_inter_fortran_05-25.xvg" u ($1):($2) lw 8 ti , "rdf_inter_fortran_05-25.xvg" u ($1):($2) lw 8 ti , "rdf_inter_fortran_05-25.xvg" u ($1):($2) lw 8 ti
的价值在于它可以修改脚本,以便输出为:
"rdf_inter_fortran_05-25.xvg" u ($1):($2) lw 8 ti , "rdf_inter_fortran_05-25.xvg" u ($1):($3) lw 8 ti , "rdf_inter_fortran_05-25.xvg" u ($1):($4) lw 8 ti , "rdf_inter_fortran_05-25.xvg" u ($1):($5) lw 8 ti
呃..........是吗? –
我修改了这个问题! –