我在Python 3.5.3中编写了一个脚本,它从文件中获取用户名/密码组合并将它们写入另一个文件。该脚本是用Windows 10在机器上编写的,并且工作正常。但是,当我试图在运行Yosemite的MacBook上运行脚本时,出现了与ASCII编码有关的错误。UnicodeDecodeError:'ascii'编解码器无法解码位置2370中的字节0xaa:序号不在范围内(128)
相关的功能是这样的:
def buildDatabase():
print("Building database, this may take some time...")
passwords = open("10-million-combos.txt", "r") #File with user/pword combos.
hashWords = open("Hashed Combos.txt", "a") #File where user/SHA-256 encrypted pwords will be stored.
j = 0
hashTable = [[ None ] for x in range(60001)] #A hashtable with 30,000 elements, quadratic probing means size must = 2 x the final size + 1
for line in passwords:
toSearch = line
i = q = toSearch.find("\t") #The username/pword combos are formatted: username\tpassword\n.
n = toSearch.find("\n")
password = line[i:n-1] #i is the start of the password, n is the end of it
username = toSearch[ :q] + ":" #q is the end of the username
byteWord = password.encode('UTF-8')
sha.update(byteWord)
toWrite = sha.hexdigest() #password is encrypted to UTF-8, run thru SHA-256, and stored in toWrite
skip = False
if len(password) == 0: #if le(password) is 0, just skip it
skip = True
if len(password) == 1:
doModulo = ord(password[0]) ** 4
if len(password) == 2:
doModulo = ord(password[0]) * ord(password[0]) * ord(password[1]) * ord(password[1])
if len(password) == 3:
doModulo = ord(password[0]) * ord(password[0]) * ord(password[1]) * ord(password[2])
if len(password) > 3:
doModulo = ord(password[0]) * ord(password[1]) * ord(password[2]) * ord(password[3])
assignment = doModulo % 60001
#The if block above gives each combo an assignment number for a hash table, indexed by password because they're more unique than usernames
successful = False
collision = 0
的错误如下:
Traceback (most recent call last):
File "/Users/connerboehm/Documents/Conner B/PythonFinalProject.py", line 104, in <module>
buildDatabase()
File "/Users/connerboehm/Documents/Conner B/PythonFinalProject.py", line 12, in buildDatabase
for line in passwords:
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/encodings/ascii.py", line 26, in decode
return codecs.ascii_decode(input, self.errors)[0]
UnicodeDecodeError: 'ascii' codec can't decode byte 0xaa in position 2370: ordinal not in range(128)
这里发生了什么?我在Windows上没有收到过这个错误,而且我没有看到我尝试编码为UTF-8的任何问题。
编辑:记事本编码ANSI。更改编码(只是将数据复制并粘贴到新的.txt文件)为UTF-8解决了这个问题。
学习字符编码(如ASCII和unicode)的时候,UTF-8是一个很好的开始。 – zaph