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这种编码方式有什么问题?JSON编码问题php
<?php
include ("../includes/db_con.php");
$itemResults = mysql_query("SELECT `sold_for` FROM `items` WHERE `item_did_sell`='1'") or die();
$mIResults = mysql_query("SELECT `mi_price`, `mi_total_sold` FROM `misc_items` WHERE `mi_total_sold`>'1'") or die();
$donationResults = mysql_query("SELECT `amount` FROM `donations`") or die(mysql_error());
$total = 0;
$itemTotal = 0;
$mITotal = 0;
$donationTotal = 0;
while($row = mysql_fetch_assoc($itemResults)){
$itemTotal += $row['sold_for'];
$total += $itemTotal;
}
while($row = mysql_fetch_assoc($mIResults)){
$mITotal += ($row['mi_price'] * $row['mi_total_sold']);
$total += $mITotal;
}
while($row = mysql_fetch_assoc($donationResults)){
$donationTotal += $row['amount'];
$total += $donationTotal;
}
header("Content-Type: application/json");
$arr = array('items' => $itemTotal,'mitems' => $mITotal,'donations' => $donationTotal,'total' => $total);
$arr = json_encode($arr);
echo $arr;
include ("../includes/db_discon.php");
?>
脚本输出: {"items":1000,"mitems":0,"donations":0,"total":1000}
发生的我的客户端的JavaScript(已认证)有在我的JSON阵列的parase错误。
此脚本的*输出*是什么? – deceze 2012-02-01 01:07:21
它输出:'{“项目”:1000,“mitems”:0,“捐款”:0,“total”:1000}' – lampwins 2012-02-01 01:08:41
这是非常有效的JSON输出那里,看起来不错。 – deceze 2012-02-01 01:09:26